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diamong [38]
3 years ago
13

What integer values satisfy both inequalities? − 2 < x < 3 − 2 ≤ x < 2

Mathematics
1 answer:
NARA [144]3 years ago
6 0

Given:

The inequalities are:

-2

-2\leq x

To find:

The integer values that satisfy both inequalities.

Solution:

We have,

-2

-2\leq x

For -2, the possible integer values are

x=-1,0,1,2          ...(i)

For -2\leq x, the possible integer values are

x=-2,-1,0,1        ...(ii)

The common values of x in (i) and (ii) are

x=-1,0,1

Therefore, the integer values -1, 0 and 1 satisfy both inequalities.

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Simplify. (-6x^2 + 2y - 1) + (2x^2-5y + 3) A) -4x^2 + 3y -2 B) -4x^2 - 3y - 2 C) -4x^2 + 3y +2 D) -4x^2 -3y +2
Rasek [7]

Combine like terms

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4 0
3 years ago
Y’all I need a lot of help please help me and please show work
Nadya [2.5K]

Answer:

90

Step-by-step explanation:

no of total groups = 2+6+4=12

so in total there are 12 groups

each have equal number of members

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4 0
3 years ago
How do I solve an equation like this, one with a negative in front of parentheses?
azamat

The factor outside the parentheses is -1. Distribute using that factor.

2 - (4 - <em>x</em>) = 7<em>x</em> - 5<em>x</em>

<em />

-1 * 4 = -4 and -1 * -<em>x</em> = <em>x</em>

<em />

2 - 4 + <em>x</em> = 7<em>x</em> - 5<em>x</em>

Simplify.

-2 + <em>x</em> = 2<em>x</em>

<em>x</em> = 2<em>x</em> + 2

-<em>x</em> = 2

<em>x</em> = -2

<h3>Answer:</h3>

<em>x</em> = -2

3 0
3 years ago
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