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diamong [38]
2 years ago
13

What integer values satisfy both inequalities? − 2 < x < 3 − 2 ≤ x < 2

Mathematics
1 answer:
NARA [144]2 years ago
6 0

Given:

The inequalities are:

-2

-2\leq x

To find:

The integer values that satisfy both inequalities.

Solution:

We have,

-2

-2\leq x

For -2, the possible integer values are

x=-1,0,1,2          ...(i)

For -2\leq x, the possible integer values are

x=-2,-1,0,1        ...(ii)

The common values of x in (i) and (ii) are

x=-1,0,1

Therefore, the integer values -1, 0 and 1 satisfy both inequalities.

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Find the area of the iscoseles triangle first answer=brainliest
blsea [12.9K]

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60cm^{2}

Step-by-step explanation:

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5 0
3 years ago
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If the equation of a circle is (x - 2)2 + (y-6)2 = 4, it passes through point
san4es73 [151]

(x - 2)² + (y - 6)² = 4

You can be certain about one thing just by looking at the equation (2, 6) is the center, so, obviously the circle isnt going through this point

Since the radius is 2 if we don't move from y = 6 we have points in (0, 6) and (4, 6)

So alternative b.

To be more certain just subs the point in the x and y, if its equal, it pass through

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4 0
3 years ago
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