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Sladkaya [172]
3 years ago
6

Find the value of x

Mathematics
2 answers:
Nookie1986 [14]3 years ago
8 0

Answer: hey if you need help with math add me

Step-by-step explanation:

Maru [420]3 years ago
5 0

Answer:

x=46

Step-by-step explanation:

hope this helps

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These questions are in Spanish, someone who knows Spanish, the topic is mathematics, please.
olganol [36]

The interest that Marcos will get is 50000.

<h3>How to calculate the interest?</h3>

The following can be deduced from the information given:

Principal = 50000

Interest rate = 12.5%

Time = 8 years

The simple interest will be:

= (PRT/100)

= (50000 × 12.5 × 8)/100

= 50000

The amount that will be obtained after 8 years will be:

= Principal + Interest

= 50000 + 50000

= 10000

Learn more about interest on:

brainly.com/question/20690803

#SPJ1

4 0
2 years ago
Relationship between rational numbers and ratios
zzz [600]
A rational number is defined as a number that can be written
as a ratio of whole numbers.  If it can't then it isn't.
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3 years ago
What can you look for to tell you that an article is native advertising
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3 years ago
Differenciate log x with respect to cot x
Troyanec [42]
If you know the chain rule

\displaystyle\frac{df}{dx} = \frac{df}{dg} \frac{dg}{dx} \implies  \frac{df}{dg} = \frac{ \frac{df}{dx} }{ \frac{dg}{dx} }

hence

\displaystyle&#10; \frac{d \log x}{d \cot x} = \frac{ \frac{d \log x}{dx} }{ \frac{d \cot x}{dx} } = \frac{\frac{1}{x \ln 10}}{-\csc^2 x} = - \frac{1}{x \ln 10 \cdot \csc^2 x}

Assuming that \log x = \log_{10} x
5 0
3 years ago
A 90% confidence interval for the mean percentage of airline reservations being canceled on the day of the flight is (1.3%, 5.1%
agasfer [191]

Answer: The point estimate for the mean is 3.2% and the margin of error is 1.9% .

Step-by-step explanation:

The confidence interval for population mean is given by :-

\mu\pm E, where E is the margin of error .

Given : A 90% confidence interval for the mean percentage of airline reservations being canceled on the day of the flight is (1.3%, 5.1%).

Lower limit of the confidence interval : \mu-E=1.3\%                 (1)

Upper limit of the interval :  \mu+E=5.1\%                                 (2)

Adding (1) and (2) , we get

2\mu=6.4\%\\\\\Rightarrow\mu=3.2\%

Now, Subtracting (1) from (2) , we get

2E =3.8\%\\\\\Rightarrow\ E=1.9\%

Hence, the point estimate for the mean is 3.2% and the margin of error is 1.9% .

3 0
3 years ago
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