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3 years ago

What is the x intercept of the line below?

Mathematics

2 answers:

maw [93]3 years ago

8 0

Answer:

No x-intercept

Step-by-step explanation:

When there's an equation that has no x then it will not touch the x axis.

sukhopar [10]3 years ago

3 0

No x intercept. Max he line only goes through y

You might be interested in

A commuter crosses one of three bridges, A, B, or C, to go home from work. The commuter crosses bridge A with probability 1/3, c

mihalych1998 [28]

Answer:

0.1333 = 13.33% probability that bridge B was used.

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Arrives home by 6 pm

Event B: Bridge B used.

Probability of arriving home by 6 pm:

75% of 1/3(Bridge A)

60% of 1/6(Bridge B)

80% of 1/2(Bridge C)

$P(A) = 0.75*\frac{1}{3} + 0.6*\frac{1}{6} + 0.8*\frac{1}{2} = 0.75$

Probability of arriving home by 6 pm using Bridge B:

60% of 1/6. So

$P(A \cap B) = 0.6*\frac{1}{6} = 0.1$

Find the probability that bridge B was used.

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.1}{0.75} = 0.1333$

0.1333 = 13.33% probability that bridge B was used.

8 0

3 years ago

5. a) If a = 3 and b

kobusy [5.1K]

Answer:

Is and suppose to be plus

5 0

3 years ago

Rectangle Given:1=15 m, w=6m,A=

sashaice [31]

Answer:

$90m^2 and 144 m^2$

Step-by-step explanation:

Given :

Length of the rectangle (l)=15m

Width of the rectangle (w)= 6 m

Area of the rectangle can be calculated as :

$A=l*w\\A=(15)(6)\\A=90 m^2$

Now,

Side of square (s)=12 m

Area of the square can be find:

$A=s^2\\A=12^2\\A=144 m^2$

6 0

2 years ago

Can somebody tell me how to solve these kind of problems?

Ugo [173]

Answer: 918km^2

Step-by-step explanation:

$area(a): 1700km^2\\percentage(p): 5.75 = \frac{5.75}{100}=0.0575\\years(y): 8$

Let x be the new dimension of the area;

$x=a-(a*p*y)$

$x=(1700km^2)-(1700km^2*0.0575*8)\\x=1700km^2-782km^2\\x=918km^2$

6 0

3 years ago

Suppose the population of a certain city is 5289 thousand. It is expected to decrease to 4530 thousand in 50 years. Find the per

Tcecarenko [31]

Answer:

14.4% decrease

Step-by-step explanation:

Here is the formula for finding the percentage of decrease:

(starting value - final value) / starting value * 100.

So for your question,

$\frac{5289-4530}{5289} =.0144\\.0144 * 100 = 14.4\\$ /

There was a 14.4% decrease within 50 years.

5 0

3 years ago