Blue was not the imposter.
Answer:
Option D
Step-by-step explanation:
f(x) =
Transformed form of the function 'f' is 'g'.
g(x) = 
Property of vertical stretch or compression of a function,
k(x) = x
Transformed function → m(x) = kx
Here, k = scale factor
1). If k > 1, function is vertically stretched.
2). If 0 < k < 1, function is vertically compressed.
From the given functions, k = 
Since, k is between 0 and
, function f(x) is vertically compressed by a scale factor
.
g(x) = f(x + 4) represents a shift of function 'f' by 4 units left.
g(x) = f(x - 4) represents a shift of function 'f' by 4 units right.
g(x) = 
Therefore, function f(x) has been shifted by 4 units left to form image function g(x).
Option D is the answer.
Answer:
the answer is d
Step-by-step explanation:
Answer:
We accept the null hypothesis that the breaking strength mean is less and equal to 1750 pounds and has not increased.
Step-by-step explanation:
The null and alternative hypotheses are stated as
H0: u ≥ 1750 i.e the mean is less and equal to 1750
against the claim
Ha: u > 1750 ( one tailed test) the mean is greater than 1750
Sample mean = x`= 1754
Population mean = u = 1750
Population deviation= σ = 65 pounds
Sample size= n = 100
Applying the Z test
z= x`- u / σ/ √n
z= 1754- 1750 / 65/ √100
z= 4/6.5
z= 0.6154
The significance level alpha = 0.1
The z - value at 0.1 for one tailed test is ± 1.28
The critical value is z > z∝.
so
0.6154 is < 1.28
We accept the null hypothesis that the breaking strength mean is less and equal to 1750 pounds and has not increased.