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Talja [164]
3 years ago
8

What’s the area of this parrelogram? (There is a photo!) Please help me!

Mathematics
1 answer:
Aliun [14]3 years ago
4 0
It’s base * height so 28
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Tammaso's family used 24.5 gallons of gas to drive 548.8 miles. How many miles did they drive for each gallon of gas?
djverab [1.8K]
548.8 divided by 24.5=22.4
8 0
3 years ago
Blue is sus vote him out<br><br>#BlueIsImposter<br>or #Idiot
taurus [48]
Blue was not the imposter.
8 0
3 years ago
Given the two functions, which statement is true?
tia_tia [17]

Answer:

Option D

Step-by-step explanation:

f(x) = \text{log}_{15}x

Transformed form of the function 'f' is 'g'.

g(x) = \frac{1}{2}\text{log}_{15}(x+4)

Property of vertical stretch or compression of a function,

k(x) = x

Transformed function → m(x) = kx

Here, k = scale factor

1). If k > 1, function is vertically stretched.

2). If 0 < k < 1, function is vertically compressed.

From the given functions, k = \frac{1}{2}

Since, k is between 0 and \frac{1}{2}, function f(x) is vertically compressed by a scale factor \frac{1}{2}.

g(x) = f(x + 4) represents a shift of function 'f' by 4 units left.

g(x) = f(x - 4) represents a shift of function 'f' by 4 units right.

g(x) = \frac{1}{2}\text{log}_{15}(x+4)

Therefore, function f(x) has been shifted by 4 units left to form image function g(x).

Option D is the answer.

8 0
3 years ago
PLEASE HELP ASAP 25 POINTS
dimaraw [331]

Answer:

the answer is d

Step-by-step explanation:


4 0
4 years ago
Read 2 more answers
The breaking strengths of cables produced by a certain manufacturer have a mean, u, of 1750 pounds, and a standard deviation of
AlladinOne [14]

Answer:

We accept the null hypothesis that the  breaking strength mean is less and equal to 1750 pounds and has not increased.

Step-by-step explanation:

The null and alternative hypotheses are stated as

H0:  u ≥ 1750   i.e the mean is less and equal to 1750

against the claim

Ha: u > 1750  ( one tailed test)  the mean is greater than 1750

Sample mean = x`= 1754

Population mean = u = 1750

Population deviation= σ = 65 pounds

Sample size= n = 100

Applying the Z test

z= x`- u / σ/ √n

z= 1754- 1750 / 65/ √100

z= 4/6.5

z= 0.6154

The significance level alpha = 0.1

The z - value at 0.1 for one tailed test is ± 1.28

The critical value is z > z∝.

so

0.6154 is < 1.28

We accept the null hypothesis that the  breaking strength mean is less and equal to 1750 pounds and has not increased.

8 0
3 years ago
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