Solve for x. help pls im stressed

Two high schools are going on a field trip. One rents 8 vans and 9 buses for 228 students. The other rents 4 vans and 5 buses fo

nevsk [136]

Answer:

No. pp you can fit in a van: 6,

No. pp you can fit in a bus: 20

Step-by-step explanation:

Let v = # of pp in vans, and let b = # of pp in buses:

8v + 9b = 228,

4v + 5b = 124

If we solve this system of equations by substitution, we isolate the first eq. for v and then substitute into the bottom eq:

v = 228-9b/8,

Substitute v = 228-9b/8 into bottom eq:

[4 * 228-9b/8 + 5b = 125]

[228+b/2=124]

[228+b = 248]

[b = 20]

Now substitute 20 to find no. of pp in the vans:

v = 228 - 9(20)/8 = 228 - 180/8 = 48/8 = 6

8 0

3 years ago

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Fofino [41]

Answer:

Step-by-step explanation:

I am sorry but please give detailed question

6 0

3 years ago

Suppose we fit a regression line to predict the number of incidents of skin cancer per 1,000 people from the number of sunny day

Jet001 [13]

Answer: The incidence of skin cancer (melanoma) has been underestimated.

Step-by-step explanation: The frequency of melanoma is more than 20 times higher in whites than in black Americans. In general, the risk of melanoma in the course of life is approximately 2.6% (1 in 38) for whites, 0.1% (1 in 1.000) for black people and 0.58% (1 in 172) for Hispanics. the risk for each person can be affected by a different number of factors.

6 0

3 years ago

Evaluate the line integral, where c is the given curve. (x + 9y) dx + x2 dy, c c consists of line segments from (0, 0) to (9, 1)

viktelen [127]

$\displaystyle\int_C(x+9y)\,\mathrm dx+x^2\,\mathrm dy=\int_C\langle x+9y,x^2\rangle\cdot\underbrace{\langle\mathrm dx,\mathrm dy\rangle}_{\mathrm d\mathbf r}$

The first line segment can be parameterized by $\mathbf r_1(t)=\langle0,0\rangle(1-t)+\langle9,1\rangle t=\langle9t,t\rangle$ with $0\le t\le1$ . Denote this first segment by $C_1$ . Then

$\displaystyle\int_{C_1}\langle x+9y,x^2\rangle\cdot\mathbf dr_1=\int_{t=0}^{t=1}\langle9t+9t,81t^2\rangle\cdot\langle9,1\rangle\,\mathrm dt$
$=\displaystyle\int_0^1(162t+81t^2)\,\mathrm dt$
$=108$

The second line segment ( $C_2$ ) can be described by $\mathbf r_2(t)=\langle9,1\rangle(1-t)+\langle10,0\rangle t=\langle9+t,1-t\rangle$ , again with $0\le t\le1$ . Then

$\displaystyle\int_{C_2}\langle x+9y,x^2\rangle\cdot\mathrm d\mathbf r_2=\int_{t=0}^{t=1}\langle9+t+9-9t,(9+t)^2\rangle\cdot\langle1,-1\rangle\,\mathrm dt$
$=\displaystyle\int_0^1(18-8t-(9+t)^2)\,\mathrm dt$
$=-\dfrac{229}3$

Finally,

$\displaystyle\int_C(x+9y)\,\mathrm dx+x^2\,\mathrm dy=108-\dfrac{229}3=\dfrac{95}3$

5 0

3 years ago

Find the value of 5! A. 25 B. 20 C. 120 D. 15

zvonat [6]

Answer:

C 120

Step-by-step explanation:

7 0

2 years ago