Solve for x.<br> help pls im stressed

What are the true and false statements for If two planes intersect, then their intersection is a line. Include converse, inverse

KonstantinChe [14]

Answer and Step-by-step explanation:

Solution:

Statement:

If two planes intersect their intersection is a line.

Suppose that

P =if two planes intersect.

q = then their intersection is line.

¬p = if two planes do not intersect.

¬q = then their intersection is not a line.

Converse:

If two planes intersect their intersection is a line.

P → q

Inverse:

If two planes do not intersect, then their intersection is not a line.

¬p → ¬q

Contrapositive:

If two planes intersection is not a line, then they do not intersect.

¬q → ¬p

3 0

3 years ago

I needed help but then i found the answer

Alenkinab [10]

1/2 × 5 2/3 × 3 = 5

the 2's cancel giving you 5 × 1/3 × 3

then the 3's cancel giving you 5 × 1

and 5 × 1 is 5.

4 0

2 years ago

find the angle between the vectors. (first find the exact expression and then approximate to the nearest degree. ) a=[1,2,-2]. B

SashulF [63]

Answer:

$\theta = cos^{-1} (\frac{10}{\sqrt{9} \sqrt{25}})=cos^{-1} (\frac{10}{15}) = cos^{-1} (\frac{2}{3}) = 48.190$

Since the angle between the two vectors is not 180 or 0 degrees we can conclude that are not parallel

And the anfle is approximately $\theta \approx 48$

Step-by-step explanation:

For this case first we need to calculate the dot product of the vectors, and after this if the dot product is not equal to 0 we can calculate the angle between the two vectors in order to see if there are parallel or not.

a=[1,2,-2], b=[4,0,-3,]

The dot product on this case is:

$a b= (1)*(4) + (2)*(0)+ (-2)*(-3)=10$

Since the dot product is not equal to zero then the two vectors are not orthogonal.

Now we can calculate the magnitude of each vector like this:

$|a|= \sqrt{(1)^2 +(2)^2 +(-2)^2}=\sqrt{9} =3$

$|b| =\sqrt{(4)^2 +(0)^2 +(-3)^2}=\sqrt{25}= 5$

And finally we can calculate the angle between the vectors like this:

$cos \theta = \frac{ab}{|a| |b|}$

And the angle is given by:

$\theta = cos^{-1} (\frac{ab}{|a| |b|})$

If we replace we got:

$\theta = cos^{-1} (\frac{10}{\sqrt{9} \sqrt{25}})=cos^{-1} (\frac{10}{15}) = cos^{-1} (\frac{2}{3}) = 48.190$

Since the angle between the two vectors is not 180 or 0 degrees we can conclude that are not parallel

And the anfle is approximately $\theta \approx 48$

3 0

2 years ago

Y-9=26<br> Can anyone help me with this question

statuscvo [17]

Answer:

Y = 35

Step-by-step explanation:

6 0

2 years ago

Ppllslslssllslslssl. awaaawwwwnnnssseeeerr thhhhhiissssss pplllslsssllslsls

Vlad1618 [11]

D is the correct answer

3 0

2 years ago

Read 2 more answers

Solve for x. help pls im stressed