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Hoochie [10]
3 years ago
7

Need help with 6 dont know it

Mathematics
2 answers:
Leokris [45]3 years ago
8 0
Pretty sure it’s D
Since 180 -95.5 is 84.5 then divide by 2 since both sides are the same. You get 42.26
pickupchik [31]3 years ago
5 0

Answer:

It should be 42.25 instead

Step-by-step explanation:

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The cost of renting a car for a day is $0.70 per mile plus a $20 flat fee
Andreyy89

Answer:

a) y = .70x + 20

-To find this, use the rate as x since it will change based on the number of miles. Since 20 is a flat fee, it can be added at the end as a constant.

b) This graph forms a straight line.

-This is because the answer in a is a linear equation.

c) The slope is .70 and the y-intercept is 20.

-For this one, the y-intercept is always the constant at the end of the equation and the slope is the coefficient of x.



5 0
2 years ago
A couple of college students frustrated with the current class registration process decide to survey 500 random students on camp
aleksklad [387]
<h3>♫ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ♫</h3>

➷ Standard deviation = \sqrt{(n*p)(1 - p)}

Substitute the values in:

\sqrt{(500 *0.84)(1-0.84)} = 8.1975...

This can be rounded to give an approximate answer of 8.2

The answer is option A.

<h3><u>✽</u></h3>

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8 0
3 years ago
which of the following correctly describes the end behavior of the polynomial function, f(x)=2x^4-3x^2+2x
inna [77]

Answer:

Both ends go up.


Step-by-step explanation:


4 0
3 years ago
Read 2 more answers
If you are allowed to use numbers 1 – 20 and need to choose the passcode of an exact 4 digit code, how many possibilities are th
VMariaS [17]

Since in a pass code, the placement of the digits is important, therefore this means that to solve for the total number of possibilities we have to make use of the principle of Permutation. The formula for calculating the total number of possibilities using Permutation is given as:

P = n! / (n – r)!

where,

n = is the total amount of numbers to choose from = 20

r = is the total number of digits needed in the passcode = 4

 

Therefore solving for the total possibilities P:

P = 20! / (20 – 4)!

P = 20! / 16!

P = 116,280

 

<span>Hence there are a total of 116,280 possibilities of pass codes.</span>

4 0
2 years ago
write an inequality that represents the phrase the sum of 1 and y is greater than or equal to 3 .Check to see if y =1 is a soult
Volgvan
1+y≥3
1+1≥3 is not true so y=1 is not a solution.

Hope this helps:)<span />
8 0
3 years ago
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