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Oliga [24]
3 years ago
8

Estimate. Round to the greatest place value. Circle whether the estimate is greater then or less then the actual product.

Mathematics
1 answer:
nataly862011 [7]3 years ago
4 0

Answer:

The estimate is greater then.

Step-by-step explanation:

143*2=286

286*2=572 not 6,517

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Mary, who is sixteen years old, is four times as old as her brother. how old will mary be when she is twice as old as her brothe
mojhsa [17]
Mary<span> is 2x = 2*12 = </span>24 years old<span>.</span>
6 0
3 years ago
An isotope decays at a rate of -0.0049% per year. Find the half life. (show the work)
cricket20 [7]

Answer:

  14,146 years

Step-by-step explanation:

The annual multiplier is (1 -0.0049%) = 0.999951. We want to find the number of times this needs to be multiplied to make the product 1/2.

  0.5 = 0.999951^t

  log(0.5) = t·log(0.999951)

  log(0.5)/log(0.999951) = t ≈ 14,145.514

The half-life is about 14,146 years.

7 0
3 years ago
Here is a polygon.
solmaris [256]

Answer:

The answer is a dilation with a scale factor less than 1 and then a reflection.

Step-by-step explanation:

4 0
2 years ago
Find the area of a circle with a circumference of 6.28 units
viktelen [127]

Answer:

area of the circle = 3.14 square units

Step-by-step explanation:

Circumference of the circle formula is 2\pir

where r is the radius of the circle

given circumference = 6.28

2\pir = 6.28

Value of pi is 3.14

2*3.14 * r= 6.28

6.28 r = 6.28

divide by 6.28 on both sides

r = 1

radius = 1

Area of the circle = \pi r^2

= 3.14 *1*1 = 3.14


6 0
3 years ago
For a sample of eight​ bears, researchers measured the distances around the​ bears' chests and weighed the bears. Minitab was us
ExtremeBDS [4]

Answer:

There is a linear correlation between chest size and weight,0.8482

Step-by-step explanation:

Given that for a sample of eight​ bears, researchers measured the distances around the​ bears' chests and weighed the bears.

the value of the linear correlation coefficient is r = 0.921.

i.e. there is a strong positive correlation from the value of r.

H_0: r=0\\H_1: r\neq 0

(Two tailed test at 5% level for correlation coefficient)

Test statistic t = \frac{r\sqrt{n-2 } }{\sqrt{1-r^2}} \\=5.791

p value <0.00001

Since p is less than 0.05 we reject H0

a) There is a  linear correlation between chest size andweight

b)--  R^2 = 0.8482 proportion of the variation in weight can be explainedby the linear relationship between weight and chest size

3 0
3 years ago
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