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mash [69]
3 years ago
6

Part B: Raymond claims that = 74. Rose argues that a

Mathematics
1 answer:
N76 [4]3 years ago
8 0

Answer:

there is no real question, once you add one I'll be glad to help, but with this knowledge, I can't

Step-by-step explanation:

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Please help.<br> Algebra.
Akimi4 [234]

1. A

Since parallel lines never cross, then there can be no intersection; that is, for a system of equations that graphs as parallel lines, there can be no solution. This is called an "inconsistent" system of equations, and it has no solution.

--------------------------------------------------------------------------------------------------------------

2. C

That's right. If a system of equations has a solution, then their graphs intersect,  and the point where they intersect is the solution because it's the point that  satisfies each equation in the system.

Straight-line graphs with the same slope are parallel lines, and they never intersect,  which is another way of saying they have no solution.

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3 years ago
Write an equation of the line containing the point (3,5) and perpendicular to the line 4x-3y=5
ICE Princess25 [194]

Answer:

Step-by-step explanation:

In order to write the equation of the line perpendicular to the given line, we first have to know what the slope of the given line is, and there's no way to tell by looking at it in its current form, which is standard. We need to solve that equation for y to determine the slope of that line. Solving for y:

-3y=-4x+5 and

3y = 4x - 5 (just change all the signs so our y term isn't negative anymore...yes, you're "allowed" to do that!) and

y=\frac{4}{3}x-\frac{5}{3} So we can see now that the slope of this line is 4/3. That means that the perpendicular slope is -3/4. Passing through the given point (3, 5):

y-5=-\frac{3}{4}(x-3)* and

y-5=-\frac{3}{4}x+\frac{9}{4} and

y=-\frac{3}{4}x+\frac{9}{4}+\frac{20}{4} so

y=-\frac{3}{4}x+\frac{29}{4}** and, in standard form:

4y = -3x + 29 and

3x + 4y = 29***

* : point-slope form

** : slope-intercept form

*** : standard form

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3 years ago
Can someone please help me with question 4
bazaltina [42]
Yes what is the four question
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3 years ago
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