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ira [324]
3 years ago
12

What is the apparent solution to the system in the graph

Mathematics
1 answer:
Mademuasel [1]3 years ago
6 0

Answer:

(2, 1)

Step-by-step explanation:

The solution is the point where the two lines intersect. In this case, that is (2, 1)

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16. Solve the equation. Check the solution.
harina [27]
Hi there

a/(a² - 36) + 2/(a-6) = 1/(a+6)
a/(a+6)(a-6) + 2/(a-6) = 1/(a+6)
Now we need to multiply the terms by (a+6)(a-6)
a + 2(a+6) = 1(a-6)
a + 2a + 12 = a - 6
3a + 12 = a - 6
3a - a = -6 - 12
2a = -18
Divide both sides by 2
2a/2 = -18/2
a = -9
Thus, The correct option is A


I hope that's help !

Good luck !

 
8 0
3 years ago
One part of Clare’s job at an environmental awareness organization is to answer the phone to collect donations. The table shows
Arisa [49]

Answer:

One part of Clare’s job at an environmental awareness organization is to answer the phone to collect donations. The table shows the number of hours she worked each week, , and the amount of donations in dollars, , that the organization collected each week for 10 weeks.

Step-by-step explanation:

u.w.u

6 0
2 years ago
A town has a population of 5000 and grows at 4% every year. What will be the population after 7 years, to the nearest whole numb
alexdok [17]
Equation:5000(1+0.04)^7
Answer: approximately 6579.65 or 6580
8 0
3 years ago
Read 2 more answers
An insurance agent earns a base salary of $28,000, a commission of 2% of sales, and receives an additional fee of $9.00 for each
BaLLatris [955]
I agree it is 798!!
4 0
3 years ago
Read 2 more answers
Question 3 (4 MARKS) Find the equation of the tangents to the curve of the function with rule y = x^2 at the points where x = a
Arte-miy333 [17]

Answer:

(0 , -a²)

Step-by-step explanation:

tangent at x = a and x = -a

y = x²     (a , a²) and (-a , a²) must be on the curve and tangent to curve

gradient dy/dx = 2x

slope (m) at x = a is <u>2a</u>     and slope (m') at x=-a is<u> -2a</u>

line1: (y - a²) / (x - a) = 2a

        y - a² = 2a (x - a)                           y = 2ax - a²   ... (1)

line2: (y - a²) / (x + a) = - 2a                   y = -2ax- a²   ... (2)

(1) - (2): 4ax = 0       a≠0    x = 0

y = - a²

I wish I did it right, or ....

3 0
3 years ago
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