F(t) can be factored to find the zeros.
.. f(t) = -5(t -5)(t +2) . . . . f(t) = 0 for t=-2, t=5
The object hits the ground after 5 seconds.
Answer:
462 paths from A to B
Step-by-step explanation:
The question is incomplete. However, a possible question is to determine the number of possible paths on the grid map.
The first step is to represent the grid map itself. (See attachment 1)
From the question, we understand that:
- Only right movement is allowed in the horizontal direction
- Only up movement is allowed in the vertical direction
There are a several number of ways to navigate through. However, one possible way is in attachment 2
In attachment 2,
- R represents the right movement
- U represents the up movement
And we have:
and 
The number of possible paths (N) is then calculated as:
Substitute values for N and U
<em>Hence, there are 462 possible paths from A to B</em>
Answer:
A 90
Step-by-step explanation:
multiple ways to prove this.
e.g. since the angle between the two lines from the center of the circle to the 2 tangent touching points is 90 degrees (that is the meaning of these 90 degrees here as the angle of the circle segment defined by the 2 tangent touching points and the circle center), the tangents have the same "behavior" as tan and cot = the tangents at the norm circle at 0 and 90 degrees. they hit each other outside of the circle again at 90 degrees.
another way
imagine the two right triangles of the tangents crossing point to the circle center and the tangent/circle touching points.
the Hypotenuse of each triangle is cutting the 90 degree angle of the circle segment exactly in half (due to the symmetry principle). so the angle between radius side and Hypotenuse is 90/2 = 45 degrees.
that means also the angle of such a right triangle at the tangent crossing point is 45 degrees (as the sum of all angles in a triangle must be 180, we have the remainder of 180 - 90 - 45 = 45 degrees).
the angles of both right triangles at that point are the same, and so we can add 45+45 = 90 degrees for the total angle at the tangent crossing point.
2.45 cm= 1 in. so 100 cm must equal 39.37 in. because you already know 2.45 cm equals 1 inch and 1 metre equals 100 cm and 1 metre is equal to 39.37.
