In ∆abc, m∠cab = 2x and m∠acb = x + 30. if line segment a b is extended through point b to point d, m∠cbd = 5x − 50. what is t
1 answer:
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Answer:
B. - 4x - 5
Step-by-step explanation:
(p о n) (x) is the same thing as (p(n(x))
We know n(x) = x - 5, so let's input that into our expression
(p(x - 5))
Since we know p(x) = x^2 + 6x, let's replace the x with the new value x-5. Now our expression is:
p(x) = (x - 5)^2 + 6(x - 5)
Now all we have to do is simplify.
(x - 5)^2 is the same as: (x - 5)(x - 5)
Using the foil method, it simplifies to: x^2 - 10x + 25
6 (x - 5) = 6x - 30
Now our expression is: x^2 - 10x + 25 + 6x - 30
Combine like terms: x^2 - 4x - 5
The expression is: - 4x - 5
Answer:
The highest altitude that the object reaches is 576 feet.
Step-by-step explanation:
The maximum altitude reached by the object can be found by using the first and second derivatives of the given function. (First and Second Derivative Tests). Let be , the first and second derivatives are, respectively:
First Derivative
Second Derivative
Then, the First and Second Derivative Test can be performed as follows. Let equalize the first derivative to zero and solve the resultant expression:
(Critical value)
The second derivative of the second-order polynomial presented above is a constant function and a negative number, which means that critical values leads to an absolute maximum, that is, the highest altitude reached by the object. Then, let is evaluate the function at the critical value:
The highest altitude that the object reaches is 576 feet.