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Goshia [24]
3 years ago
7

Use the given x and y values to write a direct variation equation. x = 2, y = 30

Mathematics
2 answers:
exis [7]3 years ago
5 0

Answer:

y = 15x

Step-by-step explanation:

Given x and y are in direct variation then the equation relating them is

y = kx ← k is the constant of variation

To find k use the condition x = 2, y = 30, then

30 = 2k ( divide both sides by 2 )

15 = k

y = 15x ← equation of variation

Dovator [93]3 years ago
4 0

Answer:

y = 15x

Step-by-step explanation:

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Tall Mountain is 8,678.37 feet higher than Mt. Might. What is the elevation of Tall Mountain?
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A storage shed is to be built in the shape of a box with a square base. It is to have a volume of 686 cubic feet. The concrete f
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Answer:

Therefore the dimension of box is 7 ft by 7 ft by 14 ft.

Step-by-step explanation:

Given that, a storage shade is be built in the shape of a box with a square base.

Let the height of the box be h and the length of one side of the square base be x.

The area of the square base is = side²

                                                    =x²

The volume of the box is = area of the base × height

                                          =x²h

According to the problem,

x²h=686

\Rightarrow h=\frac{686}{x^2} .......(1)

The concrete for the base costs $5 per square foot.

The material for the base costs =$ 5x²

The material for the roof costs $9 per square foot.

The material cost for roof is =$9x²

The material for the sides costs $3.50  per square foot.

The material cost for sides =$(3.50× 4xh )

                                             =$14xh

Total cost =$(5x²+9x²+14xh)

                =$(14x²+14 xh)

Let

C = 14x²+14 xh

Putting h=\frac{686}{x^2}

C=14x^2+14 x.\frac{686}{x^2}

\Rightarrow C=14x^2+\frac{9604}{x}

Differentiating with respect to x

C'= 28x-\frac{9604}{x^2}

Again differentiating with respect to x

C''= 28+\frac{19208}{x^2}

To find the dimension set C'=0

28x-\frac{9604}{x^2}=0

\Rightarrow 28x=\frac{9604}{x^2}

\Rightarrow x^3=\frac{9604}{28}

\Rightarrow x=7

Now,

C''|_{x=7}= 28+\frac{19208}{7^2}>0

Since at x=7, C''>0, So at x=7 , The cost of material will be minimum.

The height of the box is  h=\frac{686}{x^2}

                                            =\frac{686}{7^2}

                                            =14 foot

Therefore the dimension of box is 7 ft by 7 ft by 14 ft.

The cost of the material is =14x^2+\frac{9604}{x}

                                              =14(7)^2+\frac{9604}{7}

                                             =$2,058

6 0
4 years ago
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