Please help!!!! i don't know....
1 answer:
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Answer:
Altitude of the plane is 0.5 miles.
Step-by-step explanation:
From the figure attached,
An airplane A is at height h miles observes a small airstrip at D and a factory at F, 4.8 miles apart from D.
Angle of depressions for the airstrip is 13.1° and the factory is 4.1°.
We have to calculate the airplane's altitude h.
From ΔABF,
tan4.1 =
h = 0.07168(x + 4.8) -----(1)
From ΔABD,
tan13.1 =
h = 0.2327x -----(2)
From equation (1) and (2),
0.07168(x + 4.8) = 0.2327x
0.2327x - 0.07168x = 4.8×0.07168
0.161x = 0.344
x = miles
From equation (2),
h = 0.2327×2.137
h = 0.4972 miles
h ≈ 0.5 miles
Therefore, 0.5 miles is the altitude of the plane.
Answer:
Step-by-step explanation:
<u>Slope-intercept form</u>
y= mx +c, where m is the slope and c is the y-intercept
f(x)= -2x +4
Let's rewrite this function into an equation, in the slope-intercept form.
y= -2x +4
Slope= -2
The product of the slopes of perpendicular lines is -1.
Let the slope of the perpendicular line be m.
m(-2)= -1
m= ½
y= ½x +c
To find the value of c, substitute a pair of coordinates into the equation.
When x= -4, y= -1,
-1= ½(-4) +c
-1= -2 +c
c= -1 +2
c= 1
Thus, the equation of the line is y= ½x +1.