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emmasim [6.3K]
3 years ago
13

For khan academy . Send me the answer immediately

Mathematics
1 answer:
vodomira [7]3 years ago
7 0

Answer:

plot your first point at (-3,5) then down 2 units and to the right 5 units

Step-by-step explanation:

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A submarine is cruising 8 meters below the surface. The captain orders a dive of another 17 meters. What is the new cruising dep
swat32

Answer:

25 meters.

Step-by-step explanation:

Given in the question that,

Initial depth of the submarine = 8 meters

After the order of the captain, the submarine was made to dive another 17 meters.

So, the final cruising depth of the submarine can be calculated by <u>adding the initial depth of the submarine and the depth further increased upon the order of the captain</u>.

Thus, final cruising depth of the submarine = 8 + 17 = 25 meters.

4 0
3 years ago
A copper pipe, used for plumbing from the water main to a house, is 4 meters long and has a circular cross-section 2.8 cm in dia
topjm [15]
The volume of the hose is equal to the difference of the areas of the inner and outer circles with area equal to pi d^2 / 4 multiplied by height of hose, 4 meters.  The annulus area is equal to 3.02 cm2.The volume is equal to 0.0012 cub, m .mass is <span>0.0012 </span>cub<span>, m times density. answer is 0.67 ft3.</span>
8 0
4 years ago
What are the minimum, first quartile, median, third quartile, and maximum of the data set? 60, 50, 130, 200, 180, 150, 100, 140.
Rasek [7]

Answer:

Minimum = 50

First Quartile = 80

Median = 135

Third Quartile = 165

Maximum = 200

Step-by-step explanation:

First, it is important to reorder our values into ascending order:

50, 60, 100, 130, 140, 150, 180, 200

You've correctly identified the minimum, median and maximum values, however the quartiles are where the mistakes lie.

1. In order to calculate the first quartile, you need to look at where the median of the first half of the values is, ie. 50, 60, 100, 130

The median will be the value between (or the average of) 60 and 100:

(60 + 100)/2 = 80

Thus, the first quartile is 80.

2. In order to calculate the third quartile, we must find the median of the second half of the data set, ie. 140, 150, 180, 200

The median will be the value between (or the average of) 150 and 180:

(150 + 180)/2 = 165

Thus the third quartile is 165.

I find it's always a good idea to just draw this out and label the different values on paper to make it a bit easier.

Hope that helped! If you find anything confusing just ask :)

3 0
3 years ago
-22-p=5p-6 how do i solve this
harina [27]

Answer:

I love algebra anyways  

the ans is in the picture with the steps  

(hope it helps can i plz have brainlist :D hehe)

Step-by-step explanation:

8 0
3 years ago
Which expression is equivalent to 10x2y+25x
loris [4]
Are there any answer choices? Please let me know in the comments.
3 0
3 years ago
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