All categories

2 years ago

Identify the domain of the function shown in the graph.

Mathematics

1 answer:

Citrus2011 [14]2 years ago

7 0

B because at the end of the graphed line it has arrows which indicates that the graph will go on and on. A continuous graph.

You might be interested in

If a truck averages 12 miles to the gallon, how many pounds of carbon dioxide are emitted into the atmosphere when the truck tra

77julia77 [94]

Answer: 278.30 pounds (if the gasoline does not contain ethanol)

317.12 pounds (if the gasoline does contain ethanol)

Step-by-step explanation:

If the truck averages 12 miles per gallon, then in 170 miles it consumes:

170mi/12mi = 14.17 gallons.

We know that for one gallon consumed, the carbon dioxide emitted into the atmosphere is 19.64 pounds. (assuming it does not contain ethanol)

Then for 14.17 gallons consumed, we have a emission of:

14.17*19.64 pounds = 278.30 pounds

I the gasoline contains ethanlol, for a gallon the emiision is around 22.38 pounds.

In this case the total emission is:

14.17*22.38 pounds = 317.12 pounds

3 0

3 years ago

If the original price of a table is p in the sale price of the table is p subtracted by 0.2 P which other expression represents

FrozenT [24]

Guy yygghvftthbnnxsthjcsrjkncstikvsrhuuuuuuuuuuuuuuuuuujjjjj

7 0

2 years ago

What is the answer please.... need help

mina [271]

Answer:

$f\left(x\right)=x^3-6x^2+3x+10$ is the function of the least degree has the real coefficients and the leading coefficients of 1 and with the zeros -1, 5, and 2.

Step-by-step explanation:

Given the function

$f\left(x\right)=x^3-6x^2+3x+10$

As the highest power of the x-variable is 3 with the leading coefficients of 1.

So, it is clear that the polynomial function of the least degree has the real coefficients and the leading coefficients of 1.

solving to get the zeros

$f\left(x\right)=x^3-6x^2+3x+10$

$0=x^3-6x^2+3x+10$ ∵ $f(x)=0$

$Factor\:x^3-6x^2+3x+10\::\:\left(x+1\right)\left(x-2\right)\left(x-5\right)=0$

$\left(x+1\right)\left(x-2\right)\left(x-5\right)=0$

Using the zero factor principle

if $ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)$

$x+1=0\quad \mathrm{or}\quad \:x-2=0\quad \mathrm{or}\quad \:x-5=0$

$x=-1,\:x=2,\:x=5$

Therefore, the zeros of the function are:

$x=-1,\:x=2,\:x=5$

$f\left(x\right)=x^3-6x^2+3x+10$ is the function of the least degree has the real coefficients and the leading coefficients of 1 and with the zeros -1, 5, and 2.

Therefore, the last option is true.

8 0

2 years ago

Joel cut the longest piece of fencing in order to make a right triangle. If it takes him 30 seconds to install each foot of fenc

Harrizon [31]

there is not enough info given to tell how long it would take

6 0

2 years ago

What is partial quotients

natka813 [3]

Answer:

Is an equivalent part of a proper fraction, expressed in split parts with denominators whose LCM is the denominator of the fraction.