Answer:R = r2 and, 2. the ratio of a circle's area to the square of that circle's radius is equal to A/R.
Step-by-step explanation:
Graph B is the correct answer
answer: 4s+4
(s+12)+(3s-8) distrubute --> s+12+3s-8
comibine like terms 4s+4
hopfully this helped :)
I think you meant to say the equation is
y = 2x² - 2x + 3
Differentiate both sides with respect to x :
dy/dx = 4x - 2
At the point (3, 0), the slope of the tangent line is dy/dx(3) = 4•3 - 2 = 10. Then the normal line to the curve at (3, 0) has slope -1/10.
Using the point-slope formula, the equation of the normal line is
y - 0 = -1/10 (x - 3) ⇒ y = (3 - x)/10
Answer:
1 and 3
Step-by-step explanation:
- (5^(1/3))^2 = 5^(2/3)
- (5^2)^(1/2) = 5^(2/2) = 5
- (5^2)^(1/3) = 5^(2/3)
- (5·3)^(1/2) = 5^(1/2)·3^(1/2)
- (5^(1/2))^3 = 5^(3/2)
- (5·2)^(1/3) = 5^(1/3)·2^(1/3)
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Applicable rules are ...
![\sqrt[n]{x^{m}}=x^{\frac{m}{n}}\\\\(x^{b})^{c}=x^{bc}\\\\(ab)^{c}=a^c\cdot b^c](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Bx%5E%7Bm%7D%7D%3Dx%5E%7B%5Cfrac%7Bm%7D%7Bn%7D%7D%5C%5C%5C%5C%28x%5E%7Bb%7D%29%5E%7Bc%7D%3Dx%5E%7Bbc%7D%5C%5C%5C%5C%28ab%29%5E%7Bc%7D%3Da%5Ec%5Ccdot%20b%5Ec)
