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3 years ago

What’s the sum (s+12)+(3s-8)

Mathematics

1 answer:

Nimfa-mama [501]3 years ago

5 0

answer: 4s+4

(s+12)+(3s-8) distrubute --> s+12+3s-8

comibine like terms 4s+4

hopfully this helped :)

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Question 6(Multiple Choice Worth 1 points) (06.01 LC) Choose the correct classification of 5x + 2x2 − 8 by number of terms and b

Yakvenalex [24]

Question 7: Choose the correct simplification of the expression (3x − 6)(2x2 − 4x − 5)

Answer:

7. 6x³ - 12x² + 12x + 15

Step-by-step explanation:

(3x-6)(2x² - 4x - 5)

3x • 2x² = 6x³

3x • -4x = -12x²

3x • -5 = -15

-6 • 2x² = -12x²

-6 • -4x = 24x

-6 • -5 = 30

combine terms

6x³ - 12x² - 15 - 12x² + 24x + 30

combine like terms

6x³ - 24x² + 24x + 15

hope this helps :)

in the future, only ask one question per brainly submission. thanks!

7 0

3 years ago

If g(x)= -3x+10, what is g(-5)?

Vikentia [17]

Answer:

g(-5) = -5

Step-by-step explanation:

You replace x with -5.

-3(-5) + 10 = -15

-15 + 10 = -5

The answer is -5.

5 0

2 years ago

Read 2 more answers

A random sample of n 1 = 249 people who live in a city were selected and 87 identified as a democrat. a random sample of n 2 = 1

kvasek [131]

Answer:

$CI=\{-0.2941,-0.0337\}$

Step-by-step explanation:

Assuming conditions are met, the formula for a confidence interval (CI) for the difference between two population proportions is $\displaystyle CI=(\hat{p}_1-\hat{p}_2)\pm z^*\sqrt{\frac{\hat{p}_1(1-\hat{p}_1)}{n_1}+\frac{\hat{p}_2(1-\hat{p}_2)}{n_2}$ where $\hat{p}_1$ and $n_1$ are the sample proportion and sample size of the first sample, and $\hat{p}_2$ and $n_2$ are the sample proportion and sample size of the second sample.

We see that $\hat{p}_1=\frac{87}{249}\approx0.3494$ and $\hat{p}_2=\frac{58}{113}\approx0.5133$ . We also know that a 98% confidence level corresponds to a critical value of $z^*=2.33$ , so we can plug these values into the formula to get our desired confidence interval:

$\displaystyle CI=(\hat{p}_1-\hat{p}_2)\pm z^*\sqrt{\frac{\hat{p}_1(1-\hat{p}_1)}{n_1}+\frac{\hat{p}_2(1-\hat{p}_2)}{n_2}}\\\\CI=\biggr(\frac{87}{249}-\frac{58}{113}\biggr)\pm 2.33\sqrt{\frac{\frac{87}{249}(1-\frac{87}{249})}{249}+\frac{\frac{58}{113}(1-\frac{58}{113})}{113}}\\\\CI=\{-0.2941,-0.0337\}$

Hence, we are 98% confident that the true difference in the proportion of people that live in a city who identify as a democrat and the proportion of people that live in a rural area who identify as a democrat is contained within the interval {-0.2941,-0.0337}

The 98% confidence interval also suggests that it may be more likely that identified democrats in a rural area have a greater proportion than identified democrats in a city since the differences in the interval are less than 0.

5 0

2 years ago

Enrico is designing a rectangular board for a game. He wants the ratio of the length to the

Aleks [24]

Answer:

$A(x)=\frac{6}{5}x^2$