Here, we are required to find the equation, in terms of w, that could be used to find the dimensions of the storage unit in feet.
The polynomial is;. 3w³ + 22w + 24w = 5440ft³.
From the question;
- <em>Let the width = w</em>
- <em>length,</em><em> </em><em>l</em><em> = 3w + 4</em>
- <em>height,</em><em> </em><em>h</em><em> = w + 6</em>
<em>The </em><em>volume </em><em>of </em><em>a </em><em>rectangular</em><em> </em><em>prism </em><em>is </em><em>given </em><em>by </em><em>the </em><em>product </em><em>of </em><em>its </em><em>length,</em><em> </em><em>width </em><em>and </em><em>height.</em><em> </em><em>Thus</em><em>;</em>
Volume = l × w × h
Therefore, Volume, V = (3w +4) × w × (w +6)
To obtain the required polynomial, we expand the expression for Volume above;
<em>V = (3w² + 4w) × (w + 6)</em>
<em>V = (3w² + 4w) × (w + 6)V = 3w³ + 22w² + 24w.</em>
However, the volume of the rectangular prism has been given to be 5440 cubic feet.
Therefore, the polynomial is;
3w³ + 22w + 24w = 5440ft³.
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brainly.com/question/9740998
We have to find the mass of the gold bar.
We have gold bar in the shape of a rectangular prism.
The length, width, and the height of the gold bar is 18.00 centimeters, 9.21 centimeters, and 4.45 centimeters respectively.
First of all we will find the volume of the gold bar which is given by the volume of rectangular prism:
Volume of the gold bar 
Plugging the values in the equation we get,
Volume of the gold bar 
Now that we have the volume we can find the mass by using the formula,
The density of the gold is 19.32 grams per cubic centimeter. Plugging in the values of density and volume we get:
grams
So, the mass of the gold bar is 14252.769 grams
Answer:
m∠CDE < m∠DEC < m∠ECD
OR
m∠D < m∠E < m∠C
Step-by-step explanation:
According to the angle-side inequalities theorem: In a triangle, the angle opposite to a longer side is larger, and vise versa, the side opposite to a larger angle is longer.
So, the order from smallest to largest is:
m∠CDE < m∠DEC < m∠ECD
OR
m∠D < m∠E < m∠C
