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3 years ago

Select all radical expressions that are equivalent to 5 2/3

Mathematics

2 answers:

Alexandra [31]3 years ago

8 0

Answer:

1&3

Step-by-step explanation:

i just took the test

Dennis_Churaev [7]3 years ago

5 0

Answer:

1 and 3

Step-by-step explanation:

(5^(1/3))^2 = 5^(2/3)
(5^2)^(1/2) = 5^(2/2) = 5
(5^2)^(1/3) = 5^(2/3)
(5·3)^(1/2) = 5^(1/2)·3^(1/2)
(5^(1/2))^3 = 5^(3/2)
(5·2)^(1/3) = 5^(1/3)·2^(1/3)

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Applicable rules are ...

$\sqrt[n]{x^{m}}=x^{\frac{m}{n}}\\\\(x^{b})^{c}=x^{bc}\\\\(ab)^{c}=a^c\cdot b^c$

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Vanyuwa [196]

Answer:

11/24

Step-by-step explanation:

7/8 + 11/12 + 3/4 + x = 3 km

7*3/8*3 = 21 / 24

11*2 / 12 * 2 = 22 /24

3*6 / 4*6 = 18/24

21/24 + 22/24 + 18/24 + x = 3

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x = 72/24 - 61/24

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7 0

3 years ago

A local animal rescue organization receives an average of 0.55 rescue calls per hour. Use the Poisson distribution to find the p

andreyandreev [35.5K]

Answer:

B) 0.894

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given interval.

A local animal rescue organization receives an average of 0.55 rescue calls per hour.

This means that $\mu = 0.55$

Probability that during a randomly selected hour, the organization will receive fewer than two calls.

$P(X < 2) = P(X = 0) + P(X = 1)$

In which

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-0.55}*(0.55)^{0}}{(0)!} = 0.577$

$P(X = 1) = \frac{e^{-0.55}*(0.55)^{1}}{(1)!} = 0.317$

$P(X < 2) = P(X = 0) + P(X = 1) = 0.577 + 0.317 = 0.894$

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3 years ago

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Svetlanka [38]

Answer:

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Step-by-step explanation:

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2 years ago

Z= 37 51 39 Triangles and Trigonometry

san4es73 [151]

Answer:

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So the corect answer is (51)

5 0

2 years ago

In a recent year, an author wrote 171 checks. Use the Poisson distribution to find the probability that, on a randomly selecte

sveticcg [70]

Answer: 0.3741

Step-by-step explanation:

Poison probability ;

P(x) = [U(^x) e(^-U)] ÷ x!

Where U = mean

Note: e = exponential symbol

Number of checks that year = 171

Number of days in a year = 365

U = 171/365 = 0.468

Average checks per day = 0.4685

Probability that at least one check was written per day is can be calculated by;

P(not 0) = 1 - P(0)

Therefore,

P(x) = [U(^x) e(^-U)] ÷ x!

P(0) = [ 0.4685^0 * e^-0.4685] ÷ 0!

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P(0) = 0.6259

Therefore,

P(not 0) = 1 - 0.6259 = 0.3741

4 0

3 years ago