The equation of the line in slope-intercept form is y = (1/2)x + 3 and the slope is 1/2.
<h3>What is a straight line?</h3>
A straight line is a combination of endless points joined on both sides of the point.
The slope 'm' of any straight line is given by:

As we can see in the graph the line goes from (-6, 0) and (0, 3)
Finding the slope:

m = 3/6 = 1/2
y = mx + c
y = (1/2)x + c
c is the y-intercept
c = 3
The equation:
y = (1/2)x + 3
Thus, the equation of the line in slope-intercept form is y = (1/2)x + 3 and the slope is 1/2.
Learn more about the straight line here:
brainly.com/question/3493733
#SPJ1
Answer:
x=0
Step-by-step explanation:
The line x=4 is a vertical line through the x-axis at 4. A line parallel to it will also be a line through the x-axis. It has the form x=a where a is the x-coordinates of any points on the line. Since the line crosses through (0,1), the equation is x=0.
Answer:
![\large\boxed{A^2=\left[\begin{array}{ccc}1&-12\\6&-8\end{array}\right] }](https://tex.z-dn.net/?f=%5Clarge%5Cboxed%7BA%5E2%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%26-12%5C%5C6%26-8%5Cend%7Barray%7D%5Cright%5D%20%7D)
Step-by-step explanation:
![A=\left[\begin{array}{ccc}-3&4\\-2&0\end{array}\right]\\\\A^2=\left[\begin{array}{ccc}-3&4\\-2&0\end{array}\right] \cdot\left[\begin{array}{ccc}-3&4\\-2&0\end{array}\right] =\left[\begin{array}{ccc}(-3)(-3)+(4)(-2)&(-3)(4)+(4)(0)\\(-2)(-3)+(0)(-2)&(-2)(4)+(0)(0)\end{array}\right]\\\\A^2=\left[\begin{array}{ccc}1&-12\\6&-8\end{array}\right]](https://tex.z-dn.net/?f=A%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-3%264%5C%5C-2%260%5Cend%7Barray%7D%5Cright%5D%5C%5C%5C%5CA%5E2%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-3%264%5C%5C-2%260%5Cend%7Barray%7D%5Cright%5D%20%5Ccdot%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-3%264%5C%5C-2%260%5Cend%7Barray%7D%5Cright%5D%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%28-3%29%28-3%29%2B%284%29%28-2%29%26%28-3%29%284%29%2B%284%29%280%29%5C%5C%28-2%29%28-3%29%2B%280%29%28-2%29%26%28-2%29%284%29%2B%280%29%280%29%5Cend%7Barray%7D%5Cright%5D%5C%5C%5C%5CA%5E2%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%26-12%5C%5C6%26-8%5Cend%7Barray%7D%5Cright%5D)