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3 years ago

What is the distance between the points (-6,7) and (-1,1)?

Mathematics

2 answers:

vovikov84 [41]3 years ago

5 0

Answer:

Step-by-step explanation:

The user above is correct. The square root of 61 is equal to 7.810249676 which can be rounded up to 8.

Nataly_w [17]3 years ago

4 0

Answer:

$\sqrt{61}$

Step-by-step explanation:

To find the distance, we first do B - A, where B is (-6, 7) and A is (-1, 1):

(-6, 7) - (-1, 1) = (-6+1, 7-1) = (-5, 6)

Imagine it as a triangle, where the hypotenuse is the distance, and -5 and 6 are the lengths of the sides.

To find the hypotenuse (Pythagorean Theorem): $\sqrt{(-5)^2+6^2} =\sqrt{25+36} =\sqrt{61}$

The answer is the square root of 61.

You might be interested in

A trough is 10 ft long and its ends have the shape of isosceles triangles that are 4 ft across at the top and have a height of 1

Anna11 [10]

Answer:

7.5 ft³/min

Step-by-step explanation:

Let x be the depth below the surface of the water. The height, h of the water is thus h = 10 - x.

Now, the volume of water V = Ah where A = area of isosceles base of trough = 1/2bh' where b = base of triangle = 4 ft and h' = height of triangle = 1 ft. So, A = 1/2 × 4 ft × 1 ft = 2 ft²

So, V = Ah = 2h = 2(10 - x)

The rate of change of volume is thus

dV/dt = d[2(10 - x)]/dt = -2dx/dt

Since dV/dt = 15 ft³/min,

dx/dt = -(dV/dt)/2 = -15 ft³/min ÷ 2 = -7.5 ft³/min

Since the height of the water is h = 10 - x, the rate at which the water level is rising is dh/dt = d[10 - x]/dt

= -dx/dt

= -(-7.5 ft³/min)

= 7.5 ft³/min

And the height at this point when x = 8 inches = 8 in × 1 ft/12 in = 0.67 ft is h = (10 - 0.67) ft = 9.33 ft

7 0

2 years ago

work out the equation of the line which passes through the point (-1, 2) and is paralell to the line y = x + 4

notka56 [123]

Step-by-step explanation:

working g and everything is above

hope its of help

3 0

3 years ago

A business executive bought 40 stamps for

alekssr [168]

Answer:

32 33-cent stamps, 8 23-cent stamps

Step-by-step explanation:

In order to solve this question, we need to set up a system of equations. Also known as solving for two variables (the number of each stamp).

Let's set x to be the number of 33-cent stamps. Similarly, let's set y to be the number of 23-cent stamps.

To make our first equation, let's think about the number of stamps total we have. We can say:

$x + y =40$

<em>(AKA - The number of 33-cent stamps, plus the number of 23-cent stamps, equals 40 stamps.)</em>

Now, let's make an equation for the cost of these stamps.

$0.33x + 0.23y = 12.40$

<em>(AKA - The cost of the stamps in total, should equal $12.40).</em>

So now, we have our two equations:

$x + y =40\\0.33x+0.23y=12.40$

If you have a TI-84 graphing calculator, you can go to apps -> polysmlt2 -> simultaneous eqn solver, and then input these equations into the menu. This will solve the problem for you.

If you need to do this manually, let's use substitution. Condense our first equation to make it more substitutable.

$x+y=40\\x=40-y$

Now, let's put this into our second equation.

$0.33x+0.23y=12.40\\0.33(40-y)+0.23y=12.40$

Distribute, and solve for y.

$13.2-0.33y +0.23y =12.40\\13.2-0.1y=12.40\\-0.1y=-0.8\\y=8$

Now, we plug this into one of our equations.

$x+y=40\\x+8=40\\x=32$

In the end, we have thirty-two 33-cent stamps, and eight 23-cent stamps.

3 0

1 year ago

A small manufacturing firm has 250 employees. Fifty have been employed for less than 5 years and 125 have been with the company

sukhopar [10]

Answer:

Step-by-step explanation:

Given that a small manufacturing firm has 250 employees. Fifty have been employed for less than 5 years and 125 have been with the company for over 10 years. So remaining 75 are between 5 and 10 years.

Suppose that one employee is selected at random from a list of the employees

A) Probability that the selected employee has been with the firm less than 5 years = $\frac{50}{250 } \\= 0.20$

B) Probability that the selected employee has been with the firm between 5 and 10 years

= $\frac{75}{250 } \\= 0.30$

C) Probability that the selected employee has been with the firm more than 10 years

= $\frac{125}{250} =0.50$

a) P(A) = 0.2

P(C) = 0.5

P(A or B) = 0.2+0.3 = 0.5

P(A and C) = 0 (since A and C are disjoint)

7 0

3 years ago

(06.01)The tables below show four sets of data:

Yakvenalex [24]

For it to be non-linear, the rate of change cannot be constant. For the first table the rate is a constant 1 and the second table has a constant rate of -1. The 3rd and 4th tables have no constant rate and thus are non-linear.

The 4th table is increasing while the 3rd table is decreasing.

So the 3rd table, Set C, is the only non-linear negative association between x and y.

3 0

3 years ago

Read 2 more answers