Step-by-step explanation:
Given that,
- Height of cylinder = 4 cm
- Volume of cylinder = 616 cm³
To find,
Firstly we'll find the base radius of the cylinder.
![\longmapsto\rm{V_{(Cylinder)} = \pi r^2h}\\](https://tex.z-dn.net/?f=%5Clongmapsto%5Crm%7BV_%7B%28Cylinder%29%7D%20%3D%20%5Cpi%20r%5E2h%7D%5C%5C)
<u>Accordi</u><u>ng</u><u> </u><u>to</u><u> </u><u>the</u><u> </u><u>qu</u><u>estion</u><u>,</u>
![\longmapsto\rm{616= \dfrac{22}{7} \times r^2 \times 4}\\](https://tex.z-dn.net/?f=%5Clongmapsto%5Crm%7B616%3D%20%5Cdfrac%7B22%7D%7B7%7D%20%5Ctimes%20r%5E2%20%5Ctimes%204%7D%5C%5C)
![\longmapsto\rm{616 \times 7 = 22 \times r^2 \times 4}\\](https://tex.z-dn.net/?f=%5Clongmapsto%5Crm%7B616%20%5Ctimes%207%20%3D%2022%20%5Ctimes%20r%5E2%20%5Ctimes%204%7D%5C%5C)
![\longmapsto\rm{4312 = 88 \times r^2 }\\](https://tex.z-dn.net/?f=%5Clongmapsto%5Crm%7B4312%20%3D%2088%20%5Ctimes%20r%5E2%20%7D%5C%5C)
![\longmapsto\rm{\cancel{\dfrac{4312}{88}} = r^2 }\\](https://tex.z-dn.net/?f=%5Clongmapsto%5Crm%7B%5Ccancel%7B%5Cdfrac%7B4312%7D%7B88%7D%7D%20%3D%20%20r%5E2%20%7D%5C%5C)
![\longmapsto\rm{49 = r^2 }\\](https://tex.z-dn.net/?f=%5Clongmapsto%5Crm%7B49%20%3D%20%20r%5E2%20%7D%5C%5C)
![\longmapsto\rm{\sqrt{49} = r }\\](https://tex.z-dn.net/?f=%5Clongmapsto%5Crm%7B%5Csqrt%7B49%7D%20%3D%20%20r%20%7D%5C%5C)
![\longmapsto\rm{7 \; cm = r }\\](https://tex.z-dn.net/?f=%5Clongmapsto%5Crm%7B7%20%5C%3B%20cm%20%3D%20%20r%20%7D%5C%5C)
Now,
![\longmapsto\rm{Diameter = 2r }\\](https://tex.z-dn.net/?f=%5Clongmapsto%5Crm%7BDiameter%20%3D%202r%20%7D%5C%5C)
![\longmapsto\rm{Diameter = 2(7 \; cm) }\\](https://tex.z-dn.net/?f=%5Clongmapsto%5Crm%7BDiameter%20%3D%202%287%20%5C%3B%20cm%29%20%7D%5C%5C)
![\longmapsto\bf{Diameter = 14 \; cm}\\](https://tex.z-dn.net/?f=%5Clongmapsto%5Cbf%7BDiameter%20%3D%2014%20%5C%3B%20cm%7D%5C%5C)
The required answer is 14 cm.
Answer:
The answer is 108 cm²
Step-by-step explanation:
First, you have to find the height of the parallrelogram using trogonometric formula, sinθ = oppo./hypo. :
oppo. = height
hypo. = 9 cm
θ = 59°
sin 59° = height/9
height = 9 sin 59°
= 7.715 cm (4s.f)
Given that the formula of area of parallelogram is, A = base×height. Then, you can substitute the value into the formula :
base = 14 cm
height = 7.715 cm
A = 14 × 7.715
= 108 cm² (3s.f)
If i am not wrong the question of this woyld be the measure of 1 right . Because both of these are vertical angle so they are equal to each other “><“ like that so measure of 1 is 105 tô
Answer:
Option (3)
Step-by-step explanation:
w = ![\frac{\sqrt{2}}{2}[\text{cos}(225) + i\text{sin}(225)]](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%7B2%7D%7D%7B2%7D%5B%5Ctext%7Bcos%7D%28225%29%20%2B%20i%5Ctext%7Bsin%7D%28225%29%5D)
Since, cos(225) = cos(180 + 45)
= -cos(45) [Since, cos(180 + θ) = -cosθ]
= -![\frac{\sqrt{2}}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%7B2%7D%7D%7B2%7D)
sin(225) = sin(180 + 45)
= -sin(45)
= -![\frac{\sqrt{2}}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%7B2%7D%7D%7B2%7D)
Therefore, w = ![\frac{\sqrt{2}}{2}[-\frac{\sqrt{2}}{2}+i(-\frac{\sqrt{2}}{2})]](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%7B2%7D%7D%7B2%7D%5B-%5Cfrac%7B%5Csqrt%7B2%7D%7D%7B2%7D%2Bi%28-%5Cfrac%7B%5Csqrt%7B2%7D%7D%7B2%7D%29%5D)
= ![-\frac{2}{4}(1+i)](https://tex.z-dn.net/?f=-%5Cfrac%7B2%7D%7B4%7D%281%2Bi%29)
= ![-\frac{1}{2}(1+i)](https://tex.z-dn.net/?f=-%5Cfrac%7B1%7D%7B2%7D%281%2Bi%29)
z = 1[cos(60) + i(sin(60)]
= ![[\frac{1}{2}+i(\frac{\sqrt{3}}{2})](https://tex.z-dn.net/?f=%5B%5Cfrac%7B1%7D%7B2%7D%2Bi%28%5Cfrac%7B%5Csqrt%7B3%7D%7D%7B2%7D%29)
= ![\frac{1}{2}(1+i\sqrt{3})](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%281%2Bi%5Csqrt%7B3%7D%29)
Now (w + z) = ![-\frac{1}{2}(1+i)+\frac{1}{2}(1+i\sqrt{3})](https://tex.z-dn.net/?f=-%5Cfrac%7B1%7D%7B2%7D%281%2Bi%29%2B%5Cfrac%7B1%7D%7B2%7D%281%2Bi%5Csqrt%7B3%7D%29)
= ![-\frac{1}{2}-\frac{i}{2}+\frac{1}{2}+i\frac{\sqrt{3}}{2}](https://tex.z-dn.net/?f=-%5Cfrac%7B1%7D%7B2%7D-%5Cfrac%7Bi%7D%7B2%7D%2B%5Cfrac%7B1%7D%7B2%7D%2Bi%5Cfrac%7B%5Csqrt%7B3%7D%7D%7B2%7D)
= ![\frac{(i\sqrt{3}-i)}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B%28i%5Csqrt%7B3%7D-i%29%7D%7B2%7D)
= ![\frac{(\sqrt{3}-1)i}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B%28%5Csqrt%7B3%7D-1%29i%7D%7B2%7D)
Therefore, Option (3) will be the correct option.