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3 years ago

Help please due in in 10 minutes

Mathematics

1 answer:

ElenaW [278]3 years ago

8 0

Answer:

answer is G

zeros are 3, -5

brainlist if you get this right please :)

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Lin is shopping for a couch with her dad and hears him ask the salesperson, “How much is your commission?” The salesperson says

Natali5045456 [20]

Answer:

Step-by-step explanation:

The answer is $27.23 for the commission

Work out problem:

495×5.5%=27.225

So you round that off to 27.23

When working with a problem with percentages, you always multiple to figure out how you got your and what is your answer.

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3 years ago

Which statement is true about the circumference of a circle? The circumference is equal to the radius of the circle. The circumf

Degger [83]

Answer is The circumference is found by multiplying pi by the diameter.

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3 years ago

Read 2 more answers

What is the slope of the line represented by the equation y= -1/2x+1/4

stich3 [128]

For this case we have an equation of a line of the form:

$y = mx + b$

Where:

m: It's the slope

b: It is the cutoff point with the y axis

We have the equation:

$y = - \frac {1} {2} x + \frac {1} {4}$

So, we have:

$m = - \frac {1} {2}\\b = \frac {1} {4}$

Answer:

The slope is $- \frac {1} {2}$

3 0

4 years ago

Given h(x)=(3x-4), f(x)=(-7x+2), g(x)=(9x+1), which of the following is equivalent to 2x+3?

melomori [17]

Answer: g(x)=(9x+1)

Step by step explanation:

7 0

3 years ago

The coordinates of the turning point of the parabola whose equation is y = x2 — 6x + 8 are A. (3, 35) C. (-3, 35) B. (-3, —1) D.

quester [9]

Answer:

D. (3. —1)

Step-by-step explanation:

Vertex of a quadratic function:

Suppose we have a quadratic function in the following format:

$f(x) = ax^{2} + bx + c$

It's vertex is the point $(x_{v}, y_{v})$

In which

$x_{v} = -\frac{b}{2a}$

$y_{v} = -\frac{\Delta}{4a}$

Where

$\Delta = b^2-4ac$

If a<0, the vertex is a maximum point, that is, the maximum value happens at $x_{v}$ , and it's value is $y_{v}$ .

Turning point of a quadratic function:

The turning point of a quadratic function is the vertex.

y = x2 — 6x + 8

This means that $a = 1, b = -6, c = 8$

Now, we find the vertex.

$x_{v} = -\frac{b}{2a} = -\frac{-6}{2(1)} = 3$

$\Delta = b^2-4ac = (-6)^2-4(1)(8) = 36 - 32 = 4$

$y_{v} = -\frac{4}{4(-1)} = -1$

(x,y) = (3,-1), and the correct answer is given by option D.

6 0

3 years ago