Ex: 7^3=(7×7×7) --- 7×7=49×7=343
So what you would do is you would divide the top number (numerator) by the bottom number (denominator) Like you would normally. So take 3/10 for example you would punch into a calculator 3 divided by 10 or do the work which would be
0.3
and that is how you convert a fraction into a decimal with a denominator of 10
I hope that this helped you. (:
Let
. Then differentiating, we get

We approximate
at
with the tangent line,

The
-intercept for this approximation will be our next approximation for the root,

Repeat this process. Approximate
at
.

Then

Once more. Approximate
at
.

Then

Compare this to the actual root of
, which is approximately <u>1.76929</u>2354, matching up to the first 5 digits after the decimal place.
Answer:
Line
intersects line 
Step-by-step explanation:
We are given that


Subtract one equation from other then we get



Substitute the value of x in first equation then we get

Hence, the solution
is the intersection point of two line equations .
Answer:Line
intersects line 
Answer:
3
Step-by-step explanation: