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Alex777 [14]
3 years ago
11

Please help if u can! thx

Mathematics
2 answers:
bonufazy [111]3 years ago
5 0
Using x to represent the number: Five more than a number (x+5)
Is less than 17 (>17)
x+5 < 17
Solution: x<12
Hope this helped!
Oxana [17]3 years ago
5 0

I believe this is the correct answer

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Solve for X. *<br> (1 Point)<br> x + 70<br> 76°<br> 410
Yuki888 [10]

Answer:

x = -7

Step-by-step explanation:

41 + 76 + x + 70 = 180

x + 187 = 180

x = 180 - 187

x = -7

7 0
2 years ago
Read 2 more answers
4(x+3)-4=8(1/2x+1) i need to find the solution
oee [108]
You can solve this by algebraically as well as graphically. When I tried both ways I got:  
solution is x= -2<span />
5 0
3 years ago
Which table shows a proportional relationship?? help asap​
larisa [96]

Answer:

i wanna say its the first one if its wrong im very sorry

Step-by-step explanation:

5 0
3 years ago
Write the equation of the line that is perpendicular to 3x+2y=8 and goes through the point (-5,2)
kifflom [539]

Answer:

\displaystyle y=\frac{2}{3}(x+5)+2

Step-by-step explanation:

We need to find the equation of the line perpendicular to the line 3x+2y=8 and passes through (-5,2).

The given line can be expressed as:

\displaystyle y=-\frac{3}{2}x+4

We can see the slope of this line is m1=-3/2.

The slopes of two perpendicular lines, say m1 and m2, meet the condition:

m_1.m_2=-1

Solving for m2:

\displaystyle m_2=-\frac{1}{m_1}

\displaystyle m_2=-\frac{1}{-\frac{3}{2}}

\displaystyle m_2=\frac{2}{3}

Now we know the slope of the new line, we use the slope-point form of the line:

y=m(x-h)+k

Where m is the slope and (h,k) is the point. Using the provided point (-5,2):

\boxed{\displaystyle y=\frac{2}{3}(x+5)+2}

6 0
3 years ago
QUESTION IS DOW BELOW 30 POINTS EACH PLEASE HELP PLEASE HELP PLEASE HELP
ivann1987 [24]

The required solution is ∠RQT =  202°  and ∠QTS = 51°

<h3 />

<h3>What is a cyclic quadrilateral?</h3>

A cyclic quadrilateral is a quadrilateral which has all its four vertices lying on a circle. It is also called as inscribed quadrilateral.

Its main property is that the sum of opposite angles of inscribed quadrilateral is always 180 degrees.

Now, the given circle has a cyclic quadrilateral QRST in which it is given that  ∠RQT =  202° and ∠QRS = 129°

Since,sum of the opposite angles of a cyclic quadrilateral =  180°  

⇒∠QTS + ∠QRS = 180°

⇒ ∠QTS  + ∠129° = 180°

⇒ ∠QTS = 180° - ∠129°

⇒ ∠QTS = 51°

Hence,the requires angles are ∠RQT =  202° and ∠QTS = 51°.

More about cyclic quadrilateral :

brainly.com/question/14323008

#SPJ1

5 0
2 years ago
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