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svlad2 [7]
2 years ago
9

Help i tried to do it but not sure..

Mathematics
2 answers:
nlexa [21]2 years ago
4 0

Answer:

3000

Step-by-step explanation:

<3

aleksley [76]2 years ago
4 0
3000 thats the answer
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A population has mean 187 and standard deviation 32. If a random sample of 64 observations is selected at random from this popul
Zina [86]

Answer:

11.51% probability that the sample average will be less than 182

Step-by-step explanation:

To solve this question, we have to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 187, \sigma = 32, n = 64, s = \frac{32}{\sqrt{64}} = 4

What is the probability that the sample average will be less than 182

This is the pvalue of Z when X = 182. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{182 - 187}{4}

Z = -1.2

Z = -1.2 has a pvalue of 0.1151

11.51% probability that the sample average will be less than 182

8 0
2 years ago
Point G is located at (3, −1) and point H is located at (−2, 3). Find y value for the point that is 2 over 3 the distance from p
melamori03 [73]

Answer: The answer is \dfrac{5}{3}.

Step-by-step explanation:  Given that the co-ordinates of point G and H are (3, -1) and (-2, 3) respectively.

We are to find the y-value of the point P that is located at two-third distance from point G to point H.

As shown in the attached figure, the ration in which the point P divides the line segment GH is 2 : 1.

Therefore, the co-ordinates of point P will be

\left(\dfrac{2\times (-2)+1\times 3}{2+1},\dfrac{2\times 3+1\times (-1)}{2+1}\right)\\\\\\=\left(\dfrac{-4+3}{3},\dfrac{6-1}{3}\right)\\\\=\left(\dfrac{-1}{3},\dfrac{5}{3}\right).

Thus, the y-value of the point P is \dfrac{5}{3}.

5 0
3 years ago
Read 2 more answers
The absolute value function is written f(x) = |x|. It is composed of the lines y = x and y = -x. Its domain is the real numbers
Katena32 [7]
1.
no, there will never be a negative y-value.  <span>y= |x| will always be nonnegative. |x| can be distance x is from 0 and a distance can never be negative.

</span>2.
you can define it as
y = |x| = x if x ≥ 0, -x if x < 0

absolute value can be interpreted as a function that does not allow negative real numbers, forcing them to be positive (leaving 0 alone). if the input x is more than or equal 0, then x stays positive so there is no need to do anything: "x if x ≥ 0".
if the input is less than 0, then it is an negative number and needs a negative coefficient to negate the negative: "-x if x < 0"

example: if x = -3, then it will take the "-x if x < 0" piece resulting in y = -(-3) = 3, which is what |-3| does

if x = 1, it will take the "x if x ≥ 0" piece and just have y = 1 which is what |1| does.

for x = 0, it will take the "x if x ≥ 0" and just have y = 0 which is what |0| does
4 0
2 years ago
One side of a square is represented by 5y. Which polynomial expression BEST represents the area of the square?
kompoz [17]
As area of a square is (side)^2. Here one side is 5y.so the polynomial best suits for the area of this square is (5y)(5y)=25y^2
8 0
3 years ago
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A straight line has slope 1 and goes through the points (0, -1) and (a,3). Find the value of a.
Gala2k [10]

\bf (\stackrel{x_1}{0}~,~\stackrel{y_1}{-1})\qquad (\stackrel{x_2}{a}~,~\stackrel{y_2}{3}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{3}-\stackrel{y1}{(-1)}}}{\underset{run} {\underset{x_2}{a}-\underset{x_1}{0}}}~~=~~\stackrel{\stackrel{slope}{\downarrow }}{1}\implies \cfrac{3+1}{a}=1\implies 4=a

8 0
2 years ago
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