All categories

3 years ago

3(x + 2) = 12 solve for x

Mathematics

2 answers:

Gnoma [55]3 years ago

4 0

Answer:

x = 2.

Step-by-step explanation:

3(x + 2) = 12

3x + 6 = 12

3x = 6

x = 2

Hope this helps!

hichkok12 [17]3 years ago

4 0

Answer:

Step-by-step explanation:

You might be interested in

What are the values of x that would make the line j parallel to line k? Help me please!

vagabundo [1.1K]

Answer:

For line j to be parallel to line k, then x has to be equal to 0

Step-by-step explanation:

if line j is parallel to line k, then the two angles are equal.

They are equal because they would be alternate angles and alternate angles are equal in value

Thus,

3x + 10 = 5x + 10

5x-3x = 10-10

2x = 0

x = 0

8 0

4 years ago

Fill in the blank using your knowledge of the place value units and basic facts 830 times 20 equals

siniylev [52]

830×20=16,600 because using place value we know anything ×2 you multiple that and add the zeros

6 0

4 years ago

Read 2 more answers

A circular dog bed has a

madreJ [45]

Answer:

23 inches

Step-by-step explanation:

Circumference = 2πr

72 = 2×3.142×r

Divide through by 2 × 3.142

r = $\frac{72}{2 * 3.142}$

r = 11.458 inches

Diameter = 2r

Diameter = 2* 11.458 = 22.92

= 23 inches to the nearest inch

3 0

3 years ago

Select all of the given trigonometric equations that are true statements. sin(180°) = cos(0°) cos(74°) = sin(16°) sin(20°) = cos

lara [203]

Answer:

Cos 74°= Sin 16°

Sin 20°= Cos 70°

Sin A°=Cos (90°- A°)

Step-by-step explanation:

This is because the three pairs are complementary i.e they add up to 90° and in trigonometric ratios, complementary ratios are equal.

3 0

3 years ago

A lot of laptop computers contain 20 good ones and 3 defective ones. If two are selected and tested, find the probability that a

GarryVolchara [31]

Answer: $\dfrac{63}{253}$

Step-by-step explanation:

Given : Number of good laptops =20

Number of defective ones=3

Total laptops =23

If 2 laptops were selected, then the probability that none of them was defective would be = $\dfrac{^{20}C_2}{^{23}C_2}$

$=\dfrac{\dfrac{20!}{2!18!}}{\dfrac{23!}{2!21!}}=\dfrac{19\times20}{23\times22}\\\\=\dfrac{190}{253}$

The probability that at least one will be defective= 1- P(none of them is defective)

$=1-\dfrac{190}{253}=\dfrac{63}{253}$

Hence, the probability that at least one will be defective. $=\dfrac{63}{253}$

4 0

4 years ago