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Dmitry [639]
4 years ago
12

A lot of laptop computers contain 20 good ones and 3 defective ones. If two are selected and tested, find the probability that a

t least one will be defective.
Mathematics
1 answer:
GarryVolchara [31]4 years ago
4 0

Answer: \dfrac{63}{253}

Step-by-step explanation:

Given : Number of good laptops =20

Number of defective ones=3

Total laptops =23

If 2 laptops were selected, then the probability that none of them was defective would be = \dfrac{^{20}C_2}{^{23}C_2}

=\dfrac{\dfrac{20!}{2!18!}}{\dfrac{23!}{2!21!}}=\dfrac{19\times20}{23\times22}\\\\=\dfrac{190}{253}

The probability that at least one will be defective= 1- P(none of them is defective)

=1-\dfrac{190}{253}=\dfrac{63}{253}

Hence,  the probability that at least one will be defective. =\dfrac{63}{253}

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