Answer:
5,252
Step-by-step explanation:
Let the number of boys present be b and the number of girls present be g
Now we are told these numbers are equal. This means b = g
Furthermore, if 1313 girls leave, the number of boys remaining would be twice the number of girls.
Mathematically, this can be expressed as follows:
b/(g-1313) = 2
b = 2(g-1313)
b = 2g - 2626
b + 2626 = 2g
We know that b = g from the initial equation, substituting this here yields:
g + 2626 = 2g
g = 2626
Since b = g, b = 2626 also
Total number of students = 2626 + 2626 = 5,252
its 13 people by Thursday
Step-by-step explanation:
if Ethan send the email to 3 people on Monday that means he also had the email on Monday so that's 3+1=4 and the next day would be Tuesday that's 3 more people and 3+4=7 so by tuesday there would be 7 people then theres Wednesday that's 3 more people if you do 3+7=10 that's 10 by Wednesday then theres thursday 3 more people 10+3=13 that's how I got my answer to you
Answer:
-6m+8n-6=0
Step-by-step explanation:
Answer:
A. 3 possible combinations
B. 8 4-ounce's bags and 3 3-ounce's bags
C. 2 4-ounce's bags and 11 3-ounce's bags
D. 8 4-ounce's bags and 3 3-ounce's bags
E. All solutions offer the same revenue.
Step-by-step explanation:
You have been tasked with filling 4 ounce and 3 ounce bags from a 41 ounce container of candy. Let x be the number of 4 ounce bags and y be the number of 3 ounce bags. Then

A. Find all integer solutions:
- When x=0, then 3y=41 - impossible, because 41 is not divisible by 3.
- When x=1, then 3y=37 - impossible, because 37 is not divisible by 3.
- When x=2, then 3y=33, y=11 - possible.
- When x=3, then 3y=29 - impossible, because 29 is not divisible by 3.
- When x=4, then 3y=25 - impossible, because 25 is not divisible by 3.
- When x=5, then 3y=21, y=7 - possible.
- When x=6, then 3y=17 - impossible, because 17 is not divisible by 3.
- When x=7, then 3y=13 - impossible, because 13 is not divisible by 3.
- When x=8, then 3y=9, y=3 - possible.
- When x=9, then 3y=5 - impossible, because 5 is not divisible by 3.
- When x=10, then 3y=1 - impossible, because 1 is not divisible by 3.
You get 3 possible combinations.
B. 1. 2 + 11 = 13,
2. 5 + 7 = 12,
3. 8 + 3 = 11.
The minimal number of bags is 11.
C. 1. 2·7+11·5=69 cents
2. 5·7+7·5=70 cents
3. 8·7+3·5=71 cents
The cheapest is 1st solution.
D. 1. 2·6+11·5=67 cents
2. 5·6+7·5=65 cents
3. 8·6+3·5=63 cents
The cheapest is 3rd solution.
E. 1. 2·2+11·1.50=$20.50
2. 5·2+7·1.50=$20.50
3. 8·2+3·1.50=$20.50
All solutions offer the same revenue.