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gtnhenbr [62]
3 years ago
9

Select all of the given trigonometric equations that are true statements. sin(180°) = cos(0°) cos(74°) = sin(16°) sin(20°) = cos

(70°) sin(A°) = cos(90° - A°) sin(A°) = cos(180° - A°) cos(140°) = sin(40°)
Mathematics
1 answer:
lara [203]3 years ago
3 0

Answer:

Cos 74°= Sin 16°

Sin 20°= Cos 70°

Sin A°=Cos (90°- A°)

Step-by-step explanation:

This is because the three pairs are complementary i.e they add up to 90° and in trigonometric ratios, complementary ratios are equal.

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Factor 4x^2+28x-32=0
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Let's solve your equation step-by-step.
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<span><span><span>4<span>(<span>x−1</span>)</span></span><span>(<span>x+8</span>)</span></span>=0
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svetoff [14.1K]

<u>Statement</u><u>:</u>

The base of a triangle is 3m and its height is 10 \frac{1}{2} m.

<u>To </u><u>find </u><u>out:</u>

The area of the triangle.

<u>Solution:</u>

  • Given, base = 3m, height = 10 \frac{1}{2}m
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\sf \: area \:  \:  of \:  \: a \:  \: triangle =  \frac{1}{2}  \times base \:  \times height

  • Therefore, the area of the triangle

\sf =  (\frac{1}{2}  \times 3 \times 10 \frac{1}{2} ) {m}^{2}  \\ \sf  = ( \frac{1}{2}  \times 3 \times  \frac{21}{2} ) {m}^{2}  \\  = \sf  \frac{63}{4}  {m}^{2}  \\  =   \sf 15\frac{3}{4}  {m}^{2}

<u>Answer</u><u>:</u>

The area of the triangle is \sf \: 15 \frac{3}{4}  {m}^{2}

Hope you could understand.

If you have any query, feel free to ask.

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