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maria [59]
3 years ago
13

Question 14 (Intermediate)

Mathematics
1 answer:
DENIUS [597]3 years ago
6 0
Mary needs to sell 180 bubble teas to earn $216
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A population, P(t) (in millions) in year t, increases exponentially. Suppose P(9)=16 and P(18)=24. a) Find a formula for the pop
jenyasd209 [6]

Answer:\frac{32}{3}\left ( 1.0460\right )^t

Step-by-step explanation:

Given

Population changes exponentially

P\left ( t\right )=ab^t

P\left ( 9\right )=16------1

P\left ( 9\right )=16=ab^8

P\left ( 18\right =24=ab^{18}-----2

divide 1 & 2 we get

\frac{24}{16}=\frac{b^{18}}{b^9}

\frac{3}{2}=b^9

Substitute b^9 in 1 we get

a=\frac{32}{3}

Thus P\left ( t\right )=\frac{32}{3}\left ( 1.0460\right )^t

8 0
3 years ago
Read 2 more answers
(-2.66) multiplied by (18.44)
Stells [14]

Answer:

I think the answer you're looking for is -49.05

(longer version: -49.0504)

4 0
3 years ago
What is the next two steps for solving the following equation by using the quadratic formula?
sashaice [31]
<span>2n^2 - 7n - 3 = 0
a = 2
b = -7
c =-3
Then use the Quadratic formula:
x = [-b +-sqroot(b^2 -4*a*c)] / 2*a


</span>
6 0
3 years ago
3x - 3y = -3<br>2x - y = -5​
Korolek [52]

For this case we must solve the following system of equations:

3x-3y = -3\\2x-y = -5

To solve we follow the steps below:

We multiply the second equation by -3:

-6x + 3y = 15

Thus, we have the equivalent system:

3x-3y = -3\\-6x + 3y = 15

We add the equations:

3x-6x-3y + 3y = -3 + 15\\-3x = -3 + 15\\-3x = 12\\x = \frac {12} {- 3}\\x = -4

We look for the value of the variable "y":

2 (-4) -y = -5\\-8-y = -5\\-y = -5 + 8\\-y = 3\\y = -3

Thus, the solution of the system is given by:

(x, y): (- 4, -3)

Answer:

(x, y): (- 4, -3)

4 0
3 years ago
What is the area of a square when the side length is 2/3cm
Leviafan [203]

\bf \textit{area of a square}\\\\ A=s^2~~ \begin{cases} s=length~of\\ \qquad a~side\\[-0.5em] \hrulefill\\ s=\frac{2}{3} \end{cases}\implies A=\left( \cfrac{2}{3} \right)^2\implies A=\cfrac{2^2}{3^2}\implies A=\cfrac{4}{9}

7 0
3 years ago
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