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maria [59]
3 years ago
13

Question 14 (Intermediate)

Mathematics
1 answer:
DENIUS [597]3 years ago
6 0
Mary needs to sell 180 bubble teas to earn $216
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PLEASE HELP ME THANKS IF u do
garik1379 [7]

Answer:

The third one

Step-by-step explanation:

It can't be the first one since the peak is 4 since it is the highest

It can't be the second one because the data is all different

It could be the third one since their are gaps

And It can't be the fourth one because the range is 7

So it must be the third one

6 0
3 years ago
Explain which variables would be included when using technology to calculate the present value of a lump sum and to calculate th
koban [17]

Answer:

a. Present value of a lump sum =

PV = FV / ( 1 + i )ⁿ

b. Present value of an annuity =

P = PMT x ((1 – (1 / (1 + r)⁻ⁿ )) / r)

Step-by-step explanation:

a. Present Value of a Lump sum =

PV = FV / ( 1 + i )ⁿ

Where variables in the formula are explained as follows

PV = Present Value of the given amount today

FV = Future Value of the given amount

i = Discount rate

n = Number of periods

b. Present value of an annuity is given as:

P = PMT x ((1 – (1 / (1 + r)⁻ⁿ)) / r)

The variables in the equation are explained as the follows:

P = the present value of annuity

PMT = Payment per period or the amount in each annuity payment

r =  the interest or discount rate

n = total number of periods or the number of payments left to receive

8 0
3 years ago
When the expression $-2x^2-20x-53$ is written in the form $a(x+d)^2+e$, where $a$, $d$, and $e$ are constants, then what is the
Sladkaya [172]
We start with 2 x^{2} -20x-53 and wish to write it as a(x+d) ^{2} +e

First, pull 2 out from the first two terms: 2( x^{2} -10x)-53

Let’s look at what is in parenthesis. In the final form this needs to be a perfect square. Right now we have x^{2} -10x and we can obtain -10x by adding -5x and -5x. That is, we can build the following perfect square: x^{2} -10x+25=(x-5) ^{2}

The “problem” with what we just did is that we added to what was given. Let’s put the expression together. We have 2( x-5) ^{2}-53 and when we multiply that out it does not give us what we started with. It gives us 2 x^{2} -20x+50-53=2 x^{2} -20x-3

So you see our expression is not right. It should have a -53 but instead has a -3. So to correct it we need to subtract another 50.

We do this as follows: 2(x-5) ^{2}-53-50 which gives us the final expression we seek:

2(x-5) ^{2}-103

If you multiply this out you will get the exact expression we were given. This means that:
a = 2
d = -5
e =  -103

We are asked for the sum of a, d and e which is 2 + (-5) + (-103) = -106


7 0
3 years ago
HELP MY FRIENDS PLEASE I BEG OF THEE​
Over [174]
<h2>Answer:</h2>

<u><em>The answer has to be 30. </em></u>

<h2>Step-by-step explanation:</h2>

<em>Correct me if I am incorrect but I would believe I am correct. Have a good one!</em>

<h2>✍(◔◡◔)</h2>
7 0
3 years ago
What is 12 divided by 9.00?
ddd [48]
1 1/3 repeating because you will get the dash over it
7 0
2 years ago
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