All categories

3 years ago

Find the sum of arithmetic sequences 4+8+12+16+...+400

Mathematics

2 answers:

Anit [1.1K]3 years ago

7 0

Answer:

20200

Step-by-step explanation:

a=1 × 4=4

a=2 × 4=8

a=3 × 4=12

a = 4 × 4 = 16

400 = 4 + ( n - 1 ) 4]

400 = 4 + 4n - 4

4n = 400

400 / 4n

n = 100

100 / 2 [ 4 + 400 ]

50 [ 404 ]

50 × 404

= 20200

Hope this answer helps you :)

Have a great day

Mark brainliest

mojhsa [17]3 years ago

4 0

Answer:

Step-by-step explanation:

First term = a =4

Common difference = d = 2nd term - first term

d = 8 - 4 = 4

Last term = l = 400

First we have to fin the number of terms 'n'

l = a + (n-1)d

4 + (n-1)*4 = 400

4 + 4n- 4 = 400

4n = 400 {Divide both sides by 4}

n = 400/4

n = 100

$S_{n}=\frac{n}{2}(a + l)\\\\ = \frac{100}{2}*(4+400)\\\\=50 * 404\\\\= 20200$

You might be interested in

Morgan and her family live in a rural community in Alabama. Their average monthly expenses to meet their basic needs are shown i

7nadin3 [17]

Answer:

add up all the numbers

Step-by-step explanation:

$3017

7 0

3 years ago

What’s the correct answer or this?

Harman [31]

Answer:

Height = 35 x sin(55deg) = ~28.7 feet

6 0

3 years ago

Read 2 more answers

A cone-shaped table centerpiece has a diameter of 14 cm and a slant height that measures 31 cm. What is the surface area of the

neonofarm [45]

Answer:

i think it's C hope that helps

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

37. Socks. In your sock drawer you have 4 blue socks, 5 grey socks, and 3 black ones. Half asleep one morning, you grab 2 socks

mihalych1998 [28]

Answer:

a) $\frac{1}{22}$

b) $\frac{7}{22}$

c) $\frac{5}{11}$

d) $\frac{35}{66}$

Step-by-step explanation:

Given,

Number of blue socks = 4,

Grey socks = 5,

Black socks = 3,

Total socks = 4 + 5 + 3 = 12,

Ways of choosing any 2 socks = $^{12}C_2$

$=\frac{12!}{2!10!}$

$=\frac{12\times 11}{2}$

$=6\times 11$

= 66,

a) Ways of choosing 2 blue socks = $^3C_2$

= 3,

Since, $\text{Probability}=\frac{\text{Favorable outcomes}}{\text{Total outcomes}}$

Thus, the probability of selecting 2 blue socks = $\frac{3}{66}=\frac{1}{22}$

b) Ways of choosing 2 shocks, non of them are grey socks = $^7C_2$

$=\frac{7!}{2!5!}$

$=7\times 3$

$=21$

Thus, the probability of selecting no grey socks = $\frac{21}{66}$

$=\frac{7}{22}$

c) ways of selecting atleast 1 black sock = ways of selecting 1 black sock + ways of selecting 2 black socks

$=^3C_1\times ^9C_1+^3C_2$

$=3\times 9 + 3$

$=27 + 3$

= 30,

Thus, the probability of selecting at least 1 black sock = $\frac{30}{66}$

$=\frac{5}{11}$

d) Ways of selecting a green sock = $^5C_1\times ^7C_1$

= 35,

Thus, the probability of selecting a green sock = $\frac{35}{66}$

3 0

3 years ago

Evaluate the following absolute value expression: |-6| A)6 B)-6 C)0

Doss [256]

Hello your answer is a) 6

8 0

3 years ago