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3 years ago

7

On a miniature golf course the distance from the tee to the first hole is 96 inches the distance to the second hole is 3 yards o

n the third tee the holes is 12 feet away which of the tees is farthest from the whole

1 answer:

Vitek1552 [10]3 years ago

3 0

The farthest whole from the tee is the 3 yards because 3 yard is bigger then the other numbers I hope this helped....

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What is the mean of 73 45 88 90 90 81 83

bogdanovich [222]

$amount\ of\ numbers=7\\\\Mean=\frac{sum\ of\ numbers}{amount\ of\ numbers}=\frac{73+45+88+90+90+81+83}{7}=\frac{550}{7}\approx78,6$

7 0

3 years ago

Find the next number in the pattern. 0.5 2.5 12.5 62.5

sesenic [268]

The answer is: " 312.5 " .
_________________________________________________
<u>Note</u>: In the pattern given, each number is multipled by "5" to get to the number consecutive number.
__________________________________________________
The pattern given is:
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" 0.5, 2.5, 12.5, 62.5, ____, ....." ;

Note: The first number in the pattern given is: "0.5" .

"0.5 * 5 = 2.5" ; and "2.5" is the second number in the pattern.

"2.5 * 5 = 12.5" ; and "12.5" is the third number in the pattern.

"12.5 * 5 = 62.5" ; and "62.5" is the fourth number (and final number SHOWN in the pattern).

To find the next number, we multiply "62.5" by "5" ; to get: "312.5" .
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6 0

4 years ago

Based on the graph, if Joe earned $400, how many hours did he work?

mote1985 [20]

About 45 to 46 hours

8 0

3 years ago

Read 2 more answers

Using the following equation, find the center and radius of the circle. You must show all work and calculations to receive credi

adoni [48]

Answer:

$r = 4$

The center is:

(2, -4)

Step-by-step explanation:

We have the following equation

$x^2 - 4x + y^2 + 8y = -4$

The general equation of a circle has the following form

$(x-h)^2 + (y-k)^2 = r^2$

Where r is the radius and the point (h, k) is the center of the circle

To transform the given equation in the general equation of a circumference we must use the method of square completions

Step 1

$(x^2 - 4x) + (y^2 + 8y) = -4$

<u>Step 2</u>

<u> </u>Add and subtract $(\frac{b}{2})^2$ For an equation of the form

$ax^2 +bx +c$

$(x^2 - 4x +4)-4 + (y^2 + 8y +16) -16= -4$

<u>Step 3 </u> Factor the expressions within the parentheses

$(x-2)^2-4 + (y+4)^2 -16= -4$

<u>Step 4 Simplify</u>

$(x-2)^2 + (y+4)^2= -4+16+4$

$(x-2)^2 + (y+4)^2= 4^2$

Finally

$r = 4$

The center is:

(2, -4)

7 0

3 years ago

Write the following equation in standard form: 2/3 a+5a^3 +4a^4 -2a^5

ycow [4]

Answer:

-2a^5+4a^4+5a^3+2/3a ---- apex

Step-by-step explanation:

3 0

3 years ago