Find the slope between the following points: (11,-16) and (17,-9)

How many of these pitchers can a cylinder with height 9 inches and 2r fill? Explain how you know.

irakobra [83]

Answer:

4 pitches

Step-by-step explanation:

if a cylinder with height 9 inches and radius r is filled with water, it can fill a certain pitcher. how many of these pitchers can a cylinder with height 9 inches and radius 2r fill? explain how you know.

Solution:

The volume of a cylinder is given by:

V = πr²h;

where V is the volume, r is the radius of the cylinder and h is the height of the cylinder.

A cylinder with height 9 inches and radius r can fill a certain pitcher. Therefore the volume of the cylinder is:

V = πr²h = πr²(9) = 9πr²

V = volume of pitcher = volume of cylinder with radius r = 9πr²

For a cylinder with height 9 inches and radius 2r its volume is:

V2 = πr²h = π(2r)²(9) = 36πr²

Therefore, the number of pitchers a cylinder with height 9 inches and radius 2r can fill is:

number of pitches = 36πr² / 9πr² = 4

Therefore a cylinder with height 9 inches and radius 2r can fill 4 pitches.

3 0

2 years ago

A quantity with an initial value of 3700 decays exponentially at a rate of 6% every 5

SSSSS [86.1K]

Answer:

2369.86

Step-by-step explanation:

f(36)=3700(1−0.06) ^36/5

2369.857704098921

4 0

2 years ago

Given a data set consisting of 33 unique whole number observations, its five-number summary is:

Lemur [1.5K]

Answer:

given a data set of 33 unique whole number observation,its five number sumary is [16, 29, 40 ,54, 67]

Step-by-step explanation:

The p-th percentile in an ordered (from low to high) data set is a value such that p% of the data is less than that value. The quartiles of a data set are the 25th, 50th and 75th percentiles. (The 25th percentile is usually called the first quartile, the 50th percentile is usually called the median, and the 75th percentile is usually called the third quartile.)

The formula for finding the location (or position) of the (approximate) pth percentile in an ordered (from low to high) data set is

L p=(n+1).p/100

For example, in the data set [2,4,6,8,10,12,14,16,18]

the (approximate) 60th percentile is located at position

L 60=(9+1).60/100=6

that is, the sixth data point (the value 12) is at the (approximate) 60th percentile.(Actually, only 55.6% of the data is below a 12.)

3 0

3 years ago

Sin4x.sin5x+sin4x.sin3x-sin2x.sinx=0

andreev551 [17]

Recall the angle sum identity for cosine:

cos(x + y) = cos(x) cos(y) - sin(x) sin(y)

cos(x - y) = cos(x) cos(y) + sin(x) sin(y)

==> sin(x) sin(y) = 1/2 (cos(x - y) - cos(x + y))

Then rewrite the equation as

sin(4x) sin(5x) + sin(4x) sin(3x) - sin(2x) sin(x) = 0

1/2 (cos(-x) - cos(9x)) + 1/2 (cos(x) - cos(7x)) - 1/2 (cos(x) - cos(3x)) = 0

1/2 (cos(9x) - cos(x)) + 1/2 (cos(7x) - cos(3x)) = 0

sin(5x) sin(-4x) + sin(5x) sin(-2x) = 0

-sin(5x) (sin(4x) + sin(2x)) = 0

sin(5x) (sin(4x) + sin(2x)) = 0

Recall the double angle identity for sine:

sin(2x) = 2 sin(x) cos(x)

Rewrite the equation again as

sin(5x) (2 sin(2x) cos(2x) + sin(2x)) = 0

sin(5x) sin(2x) (2 cos(2x) + 1) = 0

sin(5x) = 0 or sin(2x) = 0 or 2 cos(2x) + 1 = 0

sin(5x) = 0 or sin(2x) = 0 or cos(2x) = -1/2

sin(5x) = 0 ==> 5x = arcsin(0) + 2nπ or 5x = arcsin(0) + π + 2nπ

… … … … … ==> 5x = 2nπ or 5x = (2n + 1)π

… … … … … ==> x = 2nπ/5 or x = (2n + 1)π/5

sin(2x) = 0 ==> 2x = arcsin(0) + 2nπ or 2x = arcsin(0) + π + 2nπ

… … … … … ==> 2x = 2nπ or 2x = (2n + 1)π

… … … … … ==> x = nπ or x = (2n + 1)π/2

cos(2x) = -1/2 ==> 2x = arccos(-1/2) + 2nπ or 2x = -arccos(-1/2) + 2nπ

… … … … … … ==> 2x = 2π/3 + 2nπ or 2x = -2π/3 + 2nπ

… … … … … … ==> x = π/3 + nπ or x = -π/3 + nπ

(where n is any integer)

5 0

3 years ago

Solve the inequality below. Enter your answer as an inequality, such as x < 2/3

marin [14]

Answer:

Divide each term by -5 and simplify

Step-by-step explanation

-5/-5=1

-5/-80=16

x<16

5 0

3 years ago