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Thepotemich [5.8K]
3 years ago
6

Write an equation for the line represented in the graph below.help​

Mathematics
1 answer:
Effectus [21]3 years ago
6 0
An equation for the line presented in the graph would be y=0x+4
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Find the midpoint of the line segment with the given endpoints. 1) (-4, -9), (-6, -6)
weeeeeb [17]

Answer:

The answer is

<h2>( - 5 \: , \:  -  \frac{15}{2} )</h2>

Step-by-step explanation:

The midpoint M of two endpoints of a given line segment can be found by using the formula

<h3>M = ( \frac{x1 + x2}{2}  , \frac{y1 + y2}{2} )</h3>

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

(-4, -9), (-6, -6)

The midpoint is

<h3>M = ( \frac{ - 4 - 6}{2}  , \:  \frac{ - 9 - 6}{2} ) \\  = ( -  \frac{10}{2} , -  \frac{15}{2} )</h3>

We have the final answer as

<h3>( - 5 \: , \:  -  \frac{15}{2} )</h3>

Hope this helps you

8 0
3 years ago
IF YOU KNOW MATH PLS HELP ME
SOVA2 [1]

Answer:

x ≈ 2.55

Step-by-step explanation:

Since the triangles are congruent then DE ≡ AB , that is

DE = AB

76x - 7 = x + 184 ( subtract x from both sides )

75x - 7 = 184 ( add 7 to both sides )

75x = 191 ( divide both sides by 75 )

x ≈ 2.55 ( to the nearest hundredth )

3 0
3 years ago
An image point of a tranformation has coordinates Y'(2, -4). If the pre-image point had coordinates Y(6, -12) what was the trans
deff fn [24]

Answer: C, a Dilation

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
1. Force is a push or a
Black_prince [1.1K]

Answer:

1. C

2.B

Step-by-step explanation:

Force is a push or a pull.. can be a twist too

to make an object move you have to apply force by pushing of pulling the object.

8 0
3 years ago
Read 2 more answers
2x2 - 12x + 10<br>what are the roots​
Tcecarenko [31]

Answer:

5 & 1

Step-by-step explanation:

We can use the quadratic formula to solve this:

Quadratic Formula = \frac{-b+-\sqrt{b^2-4ac} }{2a}

So we will have 2 answers (roots).

a is the coefficient of x^2 (2)

b is the coefficient of x (-12)

c is the constant (10)

Now, substituting, we get:

x = \frac{-b+-\sqrt{b^2-4ac} }{2a}=\frac{12+-\sqrt{(-12)^2-4(2)(10)} }{2(2)}=\frac{12+-\sqrt{64} }{4}=\frac{12+-8}{4}=\frac{12+-8}{4}=5,1

Hence the roots are 5 & 1

4 0
3 years ago
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