The formula is E= kQ/ d^2
k is 9x10^9
i changed 15 cm to 0.15 m
=> 9x10^9 x 12 OVER (0.15)^2
the answer is 4.8x10^12 N/C
but this is the electric field.
to find electric field STRENGTH, it’s E= F/q and you did not give a value for the force
Answer:
The equation of the side of triangle QRS that is parallel to segment UV is:
y = x + 9
Step-by-step explanation:
I attached a pic with the procedure to find the answer. Hope it helps, good luck!
12/3. There are 4 sixteenth notes in every quarter note.