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Oxana [17]
2 years ago
9

The length of a rectangle is 5.4 cm more than 2 times the width. If the perimeter of the rectangle is 39.6 cm, what are its dime

nsions?
a. length = 4.8 cm; width = 15 cm
b. length = 15 cm; width = 4.8 cm
c. length = 15 cm; width = 10.2 cm
d. length = 4.2 cm; width = 10.2 cm
Mathematics
1 answer:
ale4655 [162]2 years ago
8 0

Answer:

Step-by-step explanation:

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A rectanglar swimming pool is three times as long as it is wide. If the perimeter of the soccer feild is 300 yards, what are the
fredd [130]

Answer:

The dimension of the rectangular pool is 112.5\times 37.5

Step-by-step explanation:

Given : A rectangular swimming pool is three times as long as it is wide. If the perimeter of the soccer field is 300 yards.

To find : What are the dimensions?

Solution :

Let the width of the rectangular pool be 'x'.

A rectangular swimming pool is three times as long as it is wide.

The length of the pool be '3x'

The perimeter of the rectangular swimming pool is P=2(l+w)

The perimeter of the soccer field is 300 yards.

Substitute the value in the formula,

300=2(3x+x)

300=2\times 4x

300=8x

x=\frac{300}{8}

x=37.5

The width of the pool is x=37.5 unit

The length of the pool is 3x=3(37.5)=112.5

Therefore, The dimension of the rectangular pool is 112.5\times 37.5

4 0
3 years ago
Given: M(-4,-1), B(-5,-3) find the midpoint
Dmitry [639]
\bf \textit{middle point of 2 points }\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%  (a,b)
M&({{ -4}}\quad ,&{{ -1}})\quad 
%  (c,d)
B&({{ -5}}\quad ,&{{ -3}})
\end{array}\qquad
%   coordinates of midpoint 
\left(\cfrac{{{ x_2}} + {{ x_1}}}{2}\quad ,\quad \cfrac{{{ y_2}} + {{ y_1}}}{2} \right)
\\\\\\
\left(\cfrac{{{ -5}}-4}{2}\quad ,\quad \cfrac{-3-1}{2} \right)
4 0
3 years ago
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A home has a room with length 22 feet and width 25 ft.
Elena L [17]

Answer:

O length = 11 inches width = 12.5 inches

Step-by-step explanation:

8 0
2 years ago
Please I need it for today
DaniilM [7]

Answer:

Which one?

Step-by-step explanation:

7 0
3 years ago
Sally is having a problem with her puppy leaving the yard so she decides to build a new fence. The length of the yard is 10 feet
Cerrena [4.2K]

The length of the yard is 25ft.

In order to find this we first need to set up variables for the length and the width. Since we don't know anything about the width, we'll set it as x. Then, we know the length is equal to ten more than three times the width. Since the width is x, we can write the length as 3x + 10. Now we can use the formula for the perimeter of a rectangle to solve for x.

2l + 2w = P

2(3x + 10) + 2(x) = 60

6x + 20 + 2x = 60

8x + 20 = 60

8x = 40

x = 5

Now that we have a value for x, we can plug into the length equation and find the length.

3x + 10

3(5) + 10

15 + 10

25

8 0
3 years ago
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