Answer:
40/42 = 20/21
Step-by-step explanation:
Step-by-step explanation:
1. If you are trying to find a linear equation from those two points, use the equation y2-y1 over x2-x1. y2-y1 just means the second point's y coordinate minus the first point's y coordinate (same goes for x2-x1).
2. So if you were to plug the coordinates into the equation, it would be: -8-8 over 8-(-1).
3. Solve to get -16/9 because -8-8=-16 and 8-(-1)=9, so -16/9. -16/9 is the slope of the line in the y=mx +b equation.
4. It would be written like y=-16/9x +b
5. Now we need to find b which is the y-intercept. To find this pick one of the points (we'll just do (-1,8)), and plug in the x and y coordinates and solve for b.
- 8=-16/9(-1) +b
- multiply -16/9 by -1 which is 16/9
- subtract from both sides for it to be 8-16/9 on the left side which is 6 2/9, and that is b
6. The complete equation is now y=-16/9x + 6 2/9
Answer:
Step-by-step explanation:
Find the LCM of 8,9 and 10.
Prime Factorization to find LCM,
8 = 2 × 2 × 2
9 = 3 × 3
10 = 2 × 5
LCM ( 8 , 9 , 10 ) = 2 × 2 × 2 × 3 × 3 × 5 =360
But 360 is not square
Now we make the pairs complete by multiplying same numbers in prime factorization of LCM.
We need one 2 and one 5 to complete the pair.
We get, Least Square number = 2 × 2 × 2 × 2 × 3 × 3 × 5 × 5 = 3600
Hope this helps
good Luck
If these 2 triangles are similar to each other, the corresponding sides have to exist in proportion to one another. The angles would be exactly the same (side length doesn't matter at all!). Going from the bigger triangle to the smaller, KL corresponds to RS; LJ corresponds to SQ; JK corresponds to QR. The ratio of KL:RS is 5:1; the ratio of LJ:SQ is 5:1; the ratiio of JK:QR is 5:1. That means that the sides are all proportionate and the triangles are similar by the SSS postulate. Now that we know that the triangles are similar, we can say that all the corresponding angles are the same by CPCTC but we had to determinte side similiarity first. Your answer is the second choice, SSS
The perimeter = sum of all sides
= 120 + 80 + 50
= 250
So 250 - 3
247
Left space for gate
Now cost of fencing = Rs 20/per meter
= 247 × 20
= Rs 4,940
Now the area of the triangular park can be found using heron's formula
S = (a+b+c)/2
S = (120+80+50)/2
S = 250/2
S = 125
Now
Herons formula = √s(s-a)(s-b)(s-c)
√125(125-120)(125-80)(120-50)
√125(5)(45)(70)
√5×5×5×5×5×3×3×5×14
After Making pairs
5×5×5×3√14
375√14
Therefore 375√14m is the area of the triangular park
Must click thanks and mark brainliest
