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2 years ago

8

Is x^2-8x+64 a perfect square trinomial

1 answer:

Ann [662]2 years ago

4 0

Answer:

No, it is not.

Step-by-step explanation:

There is no way to simply this trinomial into two identical binomials.

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☆pls help no one has helped me and I'm so confused!

motikmotik

Answer:

Step-by-step explanation:

a). $\frac{5\pm\sqrt{-4}}{3}$ = $\frac{5}{3}\pm \frac{\sqrt{-4}}{3}$

= $\frac{5}{3}\pm\frac{2\sqrt{(-1)} }{3}$

= $\frac{5}{3}\pm\frac{2i}{3}$ [Since, i = $\sqrt{(-1)}$ ]

b). $\frac{10\pm\sqrt{-16}}{2}$ = $\frac{10}{2}\pm \frac{\sqrt{-16}}{2}$

= $5\pm \frac{4\sqrt{-1}}{2}$

= 5 ± 2i [Since, i = $\sqrt{(-1)}$ ]

c). $\frac{-3\pm \sqrt{-144}}{6}$ = $-\frac{3}{6}\pm \frac{\sqrt{-144}}{6}$

= $-\frac{3}{6}\pm \frac{12\sqrt{-1}}{6}$

= $-\frac{1}{2}\pm 2\sqrt{-1}$

= $-\frac{1}{2}\pm 2i$ [Since, i = $\sqrt{(-1)}$ ]

4 0

2 years ago

What is the volume of a rectangular prism with the dimensions: base 3 1 4 cm, height 2 1 2 cm, and length 4 1 2 cm?

Doss [256]

Answer:

is b

Step-by-step explanation:

7 0

2 years ago

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What is the equation of the line that passes through the point (1,7) and is perpendicular to the graph of Y=-14X+11

vlada-n [284]

Y=1/14x might be the answer

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2 years ago

When jeremy gets his allowance he agrees to save part of it his savings and expenses are in the ratio of 7:5 if his daily allowa

nignag [31]

He saves $ 1.75 each day from his allowance.

<u><em>Explanation</em></u>

The ratio of his savings and expenses is 7 : 5

Lets assume, his savings = 7x dollar and his expenses is 5x dollar

Given that, his daily allowance is $3. So....

$7x+5x=3\\ \\ 12x=3\\ \\ x=\frac{3}{12}= \frac{1}{4}= 0.25$

So, the amount of his savings each day $=7x= (7*0.25)dollar= 1.75 dollar$

8 0

2 years ago

Use the method of ELIMINATION to solve the system. You must SHOW ALL WORK. Make sure you have an answer for both x and y.

jekas [21]

Answer:

<h3>Required <u>Answer</u><u>:</u><u>-</u></h3>

$\sf 4x+8y=10\dots\dots (1)$

$\sf -4x+2y=-30\dots\dots (2)$

by adding eq (1) and eq (2) we get

${:}\longrightarrow$ $\sf 4x+8y=20$

${:}\longrightarrow$ $\sf -4x+2y=-30$

<h2>__________________________</h2>

${:}\longrightarrow$ $\sf 10y=-10$

${:}\longrightarrow$ $\sf y={\dfrac {-10}{10}}$

${:}\longrightarrow$ ${\underline{\boxed{\bf y=-1}}}$

Substitute the value in eq (2)

${:}\longrightarrow$ $\sf -4x+2 (-1)=-30$

${:}\longrightarrow$ $\sf -4x-2=-30$

${:}\longrightarrow$ $\sf -4x=-30+2$

${:}\longrightarrow$ $\sf -4x=-28$

${:}\longrightarrow$ $\sf x={\dfrac {-28}{-4}}$

${:}\longrightarrow$ ${\underline{\boxed{\bf x=7}}}$

$\therefore$ ${\underline{\boxed{\bf (x,y)=(7,-1)}}}$

6 0

2 years ago

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