
Here we go ~
In the above question, it is given that :

A.) Find f(2) :


or

B.) Find
:

so, we can write it as :



Now, put x =
, and y = x and we will get our required inverse function ~

C.) Find
:



Answer:
Bowling ball
Step-by-step explanation:
A bowling ball has much more mass than all three of the other choices and the amount of kinetic energy is determined based on a object's mass and velocity, but in this case, all 4 balls are traveling at the same velocity. Therefore, we know that the bowling ball has much more mass so therefore it has the most kinetic energy.
6 hours because
double- 3 hours
triple- 6 hours
Answer:
60 minutes
Step-by-step explanation:
You do the simple math
Answer:
<h2>B.
5027 in²</h2><h2>
</h2>
Step-by-step explanation:
Area of a circle = π r²
where r = 80/2 = 40 in
<u>plugin value of r=40in into the formula:</u>
Area of a circle = π r²
= π (40)²
= 5027 in²