Answer:
Remember if cosecθ=1/sinθ
sinθ×cosecθ=sinθ×1/sinθ=1
CMIIW
Answer:
M(6,5) and G(2,9)
Step-by-step explanation:

B(3,6)
C(9,4)
m = [(3+9)/2 , (6+4)/2]
= (6,5)
M(5,9)
H(8,9)
G(x,y)
[(x+8)/2 , (y+9)/2]=(5,9)
(x+8)/2 = 5
x+8 = 10
x = 2
(y+9)/2 = 9
y+9 = 18
y = 9
G(2,9)
(Correct me if i am wrong)
Answer:
A.-
D.
E.
Step-by-step explanation:
Like terms must have the same variable, in this case x, and the same exponent, in this case 2. Since the original term is
, the like terms will be those that contain
, regardless of whether their coefficient or sign is different.
Analyzing the options:
A.-
We have the same variable and the same exponent
, so it is a like term.
B. 
You have the same variable x but not the same exponent. So it's not a like term of 
C.
Same variable
but as in the previous case, the exponent is different, it is a 3 and it should be a 2, so it is not a similar or like term.
D.
In this option we do have the
, so it is a like term of 
E.
It is also a like term because it contains the
.
In summary the like terms are:
A.-
D.
E.
Answer:the speed of the wind is 20 miles per hour.
Step-by-step explanation:
A Plane flies at x miles per hour in still air. This means that the normal speed of the plane is x miles per hour.
Let y represent the speed of the wind.
Flying with a tailwind, it's speed is 485 miles per hour. This means that
the total speed of the plane would be x + y. Therefore
x + y = 485 - - - - - - - - 1
Against the wind, it's air speed is only 445 miles per hour. This means that
the total speed of the plane would be x - y. Therefore
x - y = 445 - - - - - - - - - 2
Adding equation 1 and equation 2, it becomes
2x = 930
x = 930/2 = 465
Substituting x = 465 into equation 1, it becomes
465 + y = 485
y = 485 - 465
y = 20 miles per hour