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dmitriy555 [2]
3 years ago
7

12+4y^2-7 please help i will give brainliest

Mathematics
1 answer:
Dennis_Churaev [7]3 years ago
8 0

Answer: 4 2^ + 5

Step-by-step explanation:

;w;

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How to solve this help pls
Valentin [98]

Answer:

2x^{2} +\frac{7}{x}

Step-by-step explanation:

divide each by x

7 0
3 years ago
Detroit received 8 over 5 inches of snow in the morning. The city recorded of an 3 over 5inch of snow in the evening. What was t
xenn [34]

Answer:

11/5 inches

Step-by-step explanation:

total snowfall for the day = snowfall in morning + snowfall in evening

= 8 over 5 + 3 over 5 (all in inches)

= 8/5 + 3/5 (all in inches)

Since the denominators are the same (5), we can simply add the numerators up while keeping the denominator

(8/5 + 3/5) inches= (8+3)/5 inches = 11/5 inches = total snowfall for the day

7 0
2 years ago
If |u| = 10, |v| = 8, and the angle formed between them is 60°, then u · v = ?
Gre4nikov [31]
U . v  = |u| . |v| cos 60   = 10 * 8 * 0.5 = 40   This is called the scalar (or dot) product.
5 0
3 years ago
How many complex zeros does the polynomial function have?<br> f(x)=−3x^6−2x^4+5x+6
REY [17]

one way would be to factor

I can't factor it so we will have to use Descartes' Rule of Signs which is helpful for finding how many real roots you have


it goes like this:

for a polynomial with real coefients, consider f(x)=-3x^6-2x^4+5x+6.

after arranging the terms in decending order in terms of degree, count how many times the signs of the coeffients change direction and minus 2 from that number until you get to 1 or 0. that will be the number of even roots the function can have

We have (-, -, +, +). the signs changed 1 times, so it has 1 real positive root


to get the negative roots, we evaluate f(-x) and see how many times the root changes

f(-x)=-3x^6-2x^4-5x+6

signs are (-, -, -, +). there was 1 change in sign

so the function has 1 real negative root



a total of 2 real roots


a function of degree n can have at most, n roots


our function is degree 6 so it has 6 roots

if 2 are real, then the others must be complex

6-2=4 so there are 4 complex roots


you can also show that there are only 2 real roots by using a graphing utility to see that there are only 2 real roots

7 0
3 years ago
Please help
mafiozo [28]

Answer:

Easy it's a right hand child

Step-by-step explanation:

Because if both husband and wife both have right hands. And it's 10% chance the child will be left handed. Then it's possible that the child is going to be a right hand.

4 0
3 years ago
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