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Monica [59]
3 years ago
5

Just got this don’t know how to do btw it’s due tomorrow

Mathematics
1 answer:
Softa [21]3 years ago
6 0

Answer:

2 and 4 answers

Step-by-step explanation:

\frac{xy}{xv}  = \frac{yz}{vw}  = \frac{zx}{wx}

so the second is correct and forth is correct too

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What is the area of this circle? Use 3 for pi. *<br> 9 cm is the radius
vivado [14]

Answer:

254.47

Step-by-step explanation:

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4 years ago
Four is less than ten
GenaCL600 [577]
4 > 10 because this sign > is always the less sign and this < is greater
5 0
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A pair of linear equations is shown:
Murljashka [212]

Answer:

C. Graph the first equation, which has slope = −2 and y-intercept = 3, graph the second equation, which has slope = −4 and y-intercept = −1, and find the point of intersection of the two lines.

Step-by-step explanation:

The two equations are in slope intercept form which is y = mx + b where m is the slope and b is the y-intercept.

In the first equation (y = -2x + 3), -2 is the slope since it is the coefficient. "b" is 3 since it is the constant of the equation.

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3 0
3 years ago
Read 2 more answers
Factor:10z+14yz+2y=​
defon

Answer:

2(5z+7yz+y)

it can not be factored any longer

7 0
4 years ago
Plz hurry!!!! thank you!!!!
RoseWind [281]

Answer:

m\angle KLM=53.13^o

Step-by-step explanation:

see the attached figure to better understand the problem

step 1

Find the measure of angle KOM

In the triangle KOM

we have

KO=MO=r=5\ units

KM=8\ units

Applying the law of cosines

8^2=5^2+5^2-2(5)(5)cos(KOM)

64=50-50cos(KOM)

50cos(KOM)=50-64

50cos(KOM)=-14

cos(KOM)=-14/50

m\angle KOM=cos^{-1}(-14/50)

m\angle KOM=106.26^o

step 2

Find the measure of the arc KM

we know that

arc\ KM=m\angle KOM ----> by central angle

we have

m\angle KOM=106.26^o

so

arc\ KM=106.26^o

step 3

Find the measure of angle KLM

we know that

The inscribed angle is half that of the arc comprising  

m\angle KLM=\frac{1}{2}[arc\ KM]

we have

arc\ KM=106.26^o

substitute

m\angle KLM=\frac{1}{2}[106.26^o]

m\angle KLM=53.13^o

7 0
4 years ago
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