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Elena-2011 [213]
3 years ago
10

(b) Solve for d. Show each step for full credit. Circle your final answer.

Mathematics
1 answer:
andrew11 [14]3 years ago
3 0

The answer is d = g/(e-f) which you can write as d = \frac{g}{e-f}

note: don't forget the parenthesis around the "e-f" terms if you choose to write it the first way

check out the attached image for the steps done

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Solve the following system of equations. Show all work and solutions.
Hitman42 [59]
  • y=2x²+6x+1
  • y=-4x²+1

Make the equations equal and solve for x

  • 2x²+6x+1=-4x²+1
  • 6x²+6x=0
  • 6x(x+1)=0
  • 6x=0 or x+1=0
  • x=0 or x=-1

For x=0

  • y=-4(0)+1=1

For x=-1

  • y=-4(1)+1=-3

The solutions are

  • (0,1) and (-1,-3)

Graph attached

4 0
2 years ago
A Family purchased tickets to the movies in spent a total of $40.75. The family purchase five tickets there was a $.90 processi
muminat

Answer:

$7.25

Step-by-step explanation:

Total amount spent on the ticket   = $40.75

Number of ticket purchased  = 5

Processing fee per ticket  = $0.90

Unknown:

Cost of each ticket = ?

Solution:

To solve this problem, we need to find the processing fee for the 5 tickets purchase;

      Processing fee = number ticket x processing fee per ticket

      Processing fee  = 5 x 0.9  = $4.5

Now, the real cost a ticket = $40.75  - $4.5  = $36.25

So, cost per ticket is;

        Cost  = \frac{36.25}{5}   = $7.25

7 0
3 years ago
The stock at Z-Mart was 2,500 items. The stock went down 10% after the weekend. On Wednesday, 10% more stock was added. How many
crimeas [40]
2500 * 0.9 = 2250
2250 * 0.9 = 2025 current stock
7 0
3 years ago
Mindy's dog ate 5/6 of a can of food. Heather's dog ate 2/3 of a can of food. How much more did Mindy's dog eat than Heather's d
Simora [160]
1/6 a can of dog food.
6 0
3 years ago
Let us analyze the following setting. You are given a circle of unit circumference. You pickkpoints on the circle independently
garik1379 [7]

Answer:

We have been given a unit circle which is cut at k different points to produce k different arcs. Now we can see firstly that the sum of lengths of all k arks is equal to the circumference:

\small \sum_{i = 1}^{k} L_i= 2\pi

Now consider the largest arc to have length \small l . And we represent all the other arcs to be some constant times this length.

we get :

 \small \sum_{i = 1}^{k} C_i.l = 2\pi

where C(i) is a constant coefficient obviously between 0 and 1.

\small \sum_{i = 1}^{k} C_i= 2\pi/l

All that I want to say by using this step is that after we choose the largest length (or any length for that matter) the other fractions appear according to the above summation constraint. [This step may even be avoided depending on how much precaution you wanna take when deriving a relation.]

So since there is no bias, and \small l may come out to be any value from [0 , 2π] with equal probability, the expected value is then defined as just the average value of all the samples.

We already know the sum so it is easy to compute the average :

\small L_{Exp} = \frac{2\pi}{k}

7 0
3 years ago
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