Question

A coordinate plane with a line passing through the points (0, negative 1, 0) and (4, 0).

Answer 1

Answer:

x-4y=4

Step-by-step explanation:

The equation of a straight line is in slope intercept form:

y = mx + b;

where y and x are variables, m is the slope of the line and b is the y intercept.

The standard form of a line is:

Ax + By = C

where A, B and C are constants, x and y are variables

The equation of a straight line passing through the points (x₁, y₁) and (x₂, y₂) is given by:

$y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)$

Given that a line passes through the points (0, -1) and (4, 0), the equation of the line is given by:

$y-(-1)=\frac{0-(-1)}{4-0} (x-0)\\\\y+1=\frac{1}{4} x\\\\y=\frac{1}{4} x-1\\\\4y=x-4\\\\x-4y=4$