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schepotkina [342]
3 years ago
8

Solve the quadratic equation x2+8x−30=0 by completing the square.

Mathematics
1 answer:
diamong [38]3 years ago
5 0

Answer:

               \bold{x=-4\pm\sqrt{46}}

Step-by-step explanation:

(a+b)^2=a^2+2ab+b^2\\\\\\x^2+8x-30=0\\\\\underbrace{x^2+2\cdot x\cdot 4+4^2}-4^2-30=0\\\\{}\qquad(x+4)^2\,-\,16-30=0\\\\{}\qquad\ \ (x+4)^2=46\\\\ {}\qquad\ \ x+4=\pm\sqrt{46}\\\\ {}\qquad\ \ x=-4\pm\sqrt{46}

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Worth 20 points, first answer gets brainliest!
user100 [1]

Answer:

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Step-by-step explanation:

Simplifying

5x + 130 = 8x + 151

Reorder the terms:

130 + 5x = 8x + 151

Reorder the terms:

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Solving

130 + 5x = 151 + 8x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-8x' to each side of the equation.

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Add '-130' to each side of the equation.

130 + -130 + -3x = 151 + -130

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Simplifying

5 0
3 years ago
Read 2 more answers
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