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Mamont248 [21]
3 years ago
12

Can the sum of two mixed numbers be equal to 2?

Mathematics
2 answers:
Genrish500 [490]3 years ago
6 0
No it can not be that
igomit [66]3 years ago
3 0
No it cant because a mixed number is over one unless that mixed number is negative
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What is the solution to this equation 8y minus 2 equals negative 18
EleoNora [17]
8y - 2 = - 18
8y = - 16
y = - 2

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3 years ago
BD is the angle bisector of ZABC.
mojhsa [17]

Answer:

B:25°

Step-by-step explanation:

Now \angle ABC gets bisected by BD.

\angle ABD=25^{\circ}

Since, the angle is bisected, this means that the angle is split into two equal parts or the angle is halved.

We know that one of the angles is 25^{\circ} so the other angle has to be 25^{\circ} also.

Hence, the m\angle DBC=25^{\circ}.

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2 years ago
Captain Gabriela has a ship, the H.M.S. Khan. The ship is two furlongs from the dread pirate Daniel and his
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8 0
3 years ago
Read 2 more answers
Ayana has 220 coins in her piggy bank Of those 40percent are pennies. Out of the coins that are not pennies 25 percent are partn
Rzqust [24]
To find a percent of a number, multiply the percent by the number.

First we find the number of pennies.

40% of 220 =

= 40% * 220

= 0.4 * 220

= 88

88 coins are pennies.

220 - 88 = 132

132 coins are not pennies.

Now we find 25% of 132.

25% of 132 =

= 25% * 132

= 0.25 * 132

= 33

33 coins are partners.

(Did you mean quarters instead of partners?)
3 0
3 years ago
Compare the process of solving |x – 1| + 1 < 15 to that of solving |x – 1| + 1 > 15. Check all of the following you includ
zepelin [54]

The required Comparison of the inequalities are

  • The |x – 1| + 1 > 15 represents the value of x lies between 13<x<15.

The range of values encompassing the region's junction is (-13, 15).

  • If x is more than or equal to 15, then x-11+1>15 indicates the value of x is greater than or equal to 13. None of the regions in the intersection are empty.

<h3>What is inequality?</h3>

When comparing two numbers, an inequality indicates whether one is less than, larger than, or not equal to the other.

We take into account the various variables of the inequality

|x – 1| + 1 > 15

Therefore

|-x-1|+1-1<15-1

|-x-1|-1 <14

13<x<15

The required region lies between the inequality -13 <x< 15.

Simplify the inequality Ix-11+1 > 15 we get,

|x-1|+1 > 15

|x+1| +1-1 >15-1

|x-1| > 14

x> 15  

x<-13

  • If x has a value between -13 and x + 15, then the expression "|x-1|+1+115" is true. The range "(-13, 15)" contains the intersection of the region.
  • If "|x-1|+1>15" then either "x >15" or "x-13" applies to the value of x. This region's intersection is unoccupied.

Read more about inequalities

brainly.com/question/20383699

#SPJ1

7 0
2 years ago
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