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3 years ago

An angle equal to its supplement is _____ degree.

Mathematics

2 answers:

bonufazy [111]3 years ago

7 0

Answer:

90 Degrees.

The angle which is equal to its supplement is 90 degrees.

mojhsa [17]3 years ago

4 0

Answer:

Step-by-step explanation:

Let the required angle be x°

Therefore, it's supplement = (180-x)°

Now, x = 180-x

= x+x = 180

= 2x = 180°

Therefore x\ =\ \frac{180°}{2}\ =\ 90°x = 2180° = 90°

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Find the arc length of AB⌢. Round your answer to the nearest hundredth.

gizmo_the_mogwai [7]

Answer:

3.14 ft

Step-by-step explanation:

The arc AB is the minor arc of the given circle. The length l of the minor arc of a circle is given as

l = Ф°/360° × 2πr

where

Ф is the angle of the arc at the center of the circle

r is the radius of the circle and

π is a mathematical constant equivalent to 22/7

r = 8/2 = 4 ft

Hence

l = 45°/360° × 2 × 22/7 × 4

= 22/7 ft

= 3.14 ft

5 0

3 years ago

Verify each trigonometric equation by substituting identities to match the right hand side of the equation to the left hand side

lorasvet [3.4K]

Answer:

Step-by-step explanation:

cot x sec⁴ x = cot x+2 tan x +tan³x

L.H.S = cot x sec⁴x

=cot x (sec²x)²

=cot x (1+tan²x)² [ ∵ sec²x=1+tan²x]

= cot x(1+ 2 tan²x +tan⁴x)

=cot x+ 2 cot x tan²x+cot x tan⁴x

=cot x +2 tan x + tan³x [ ∵cot x tan x $=\frac{ \textrm{tan x }}{\textrm{tan x}}$ =1]

=R.H.S

(sin x)(tan x cos x - cot x cos x)=1-2 cos²x

L.H.S =(sin x)(tan x cos x - cot x cos x)

= sin x tan x cos x - sin x cot x cos x

$=\textrm{sin x cos x }\times\frac{\textrm{sin x}}{\textrm{cos x} } - \textrm{sinx}\times\frac{\textrm{cos x}}{\textrm{sin x}}\times \textrm{cos x}$

= sin²x -cos²x

=1-cos²x-cos²x

=1-2 cos²x

=R.H.S

1+ sec²x sin²x =sec²x

L.H.S =1+ sec²x sin²x

= $1+\frac{{sin^2x}}{cos^2x}$ [ $\textrm{sec x}=\frac{1}{\textrm{cos x}}$ ]

=1+tan²x $[\frac{\textrm{sin x}}{\textrm{cos x}} = \textrm{tan x}]$

=sec²x

=R.H.S

$\frac{\textrm{sinx}}{\textrm{1-cos x}} +\frac{\textrm{sinx}}{\textrm{1+cos x}} = \textrm{2 csc x}$

L.H.S= $\frac{\textrm{sinx}}{\textrm{1-cos x}} +\frac{\textrm{sinx}}{\textrm{1+cos x}}$

$=\frac{\textrm{sinx(1+cos x)+{\textrm{sinx(1-cos x)}}}}{\textrm{(1-cos x)\textrm{(1+cos x})}}$

$=\frac{\textrm{sinx+sin xcos x+{\textrm{sinx-sin xcos x}}}}{{(1-cos ^2x)}}$

$=\frac{\textrm{2sin x}}{sin^2 x}$

= 2 csc x

= R.H.S

-tan²x + sec²x=1

L.H.S=-tan²x + sec²x

= sec²x-tan²x

= $\frac{1}{cos^2x} -\frac{sin^2x}{cos^2x}$

$=\frac{1- sin^2x}{cos^2x}$

$=\frac{cos^2x}{cos^2x}$

8 0

3 years ago

at a school there are 10 students taking only chemistry, 9 students taking only physics 5 students taking both, and 16 students

sveticcg [70]

Answer:

If there are 10 students taking only chemistry, 9 students taking only physics, and 5 students only taking both chemisty and 16 students are taking neither; I would add 10+9+5+16=40 (total students) and divide 10/40 (25% chemistry) 9/40 (22.5% physics) 5/40 (12.5% both) 16/40 (40% neither)

Step-by-step explanation:

1. Determine a single event with a single outcome.

2. Identify the total number of outcomes that can occur.

3. Divide the number of events by the number of possible outcomes.

8 0

3 years ago

Read 2 more answers

How do you solve 10+5(3x-4)=2x+7

Taya2010 [7]

Answer:

$x=1\dfrac{4}{13}$