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Ksivusya [100]
2 years ago
7

Approximately how many liters are in 18 quarts?

Mathematics
2 answers:
harina [27]2 years ago
7 0

Answer:

18 liquid quarts ≈ 17 litres

Marina CMI [18]2 years ago
3 0

Answer:

18 us liquid quart =17.034 liters

Step-by-step explanation:

1) 1 us liquid quart = 0.946 liter

2) Multiply 0.946 *18 = 17.034

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Use the function shown in the table to answer the questions below .
Lubov Fominskaja [6]

Answer:

a) -6

b) 3

c) Y = -6x + 3

Step-by-step explanation:

Pick two points and find rise/run = slope

rise y1 - y2 = 9 - 3 = 6

run x1 - x2 = -1 - 0 = -1

slope = 6 / -1 = -6

The y intercept is where x = 0 which is given in the table (0,3) so

y intercept = 3

Point slope form is y = mx + b , so

y = -6x + 3

7 0
3 years ago
I did not get the right answer, please help.​
yawa3891 [41]

Answer:frfr it made hard

Step-by-step explanation:

6 0
3 years ago
Need help on this question
ololo11 [35]
45 degree between Oak street and Elm Street.
4 0
3 years ago
1 + tanx / 1 + cotx =2
Lera25 [3.4K]

Answer:

x = tan^(-1)((i sqrt(3))/2 + 1/2) + π n_1 for n_1 element Z

or x = tan^(-1)(-(i sqrt(3))/2 + 1/2) + π n_2 for n_2 element Z

Step-by-step explanation:

Solve for x:

1 + cot(x) + tan(x) = 2

Multiply both sides of 1 + cot(x) + tan(x) = 2 by tan(x):

1 + tan(x) + tan^2(x) = 2 tan(x)

Subtract 2 tan(x) from both sides:

1 - tan(x) + tan^2(x) = 0

Subtract 1 from both sides:

tan^2(x) - tan(x) = -1

Add 1/4 to both sides:

1/4 - tan(x) + tan^2(x) = -3/4

Write the left hand side as a square:

(tan(x) - 1/2)^2 = -3/4

Take the square root of both sides:

tan(x) - 1/2 = (i sqrt(3))/2 or tan(x) - 1/2 = -(i sqrt(3))/2

Add 1/2 to both sides:

tan(x) = 1/2 + (i sqrt(3))/2 or tan(x) - 1/2 = -(i sqrt(3))/2

Take the inverse tangent of both sides:

x = tan^(-1)((i sqrt(3))/2 + 1/2) + π n_1 for n_1 element Z

or tan(x) - 1/2 = -(i sqrt(3))/2

Add 1/2 to both sides:

x = tan^(-1)((i sqrt(3))/2 + 1/2) + π n_1 for n_1 element Z

or tan(x) = 1/2 - (i sqrt(3))/2

Take the inverse tangent of both sides:

Answer:  x = tan^(-1)((i sqrt(3))/2 + 1/2) + π n_1 for n_1 element Z

or x = tan^(-1)(-(i sqrt(3))/2 + 1/2) + π n_2 for n_2 element Z

4 0
3 years ago
How would I solve for x?​
vaieri [72.5K]

Answer:

x = 65

Step-by-step explanation:

First, we calculate the unknown angle of the left triangle and right triangle:180 - 62 - 50 = 68

Unknown angle for left triangle⬆️

180 - 80 - 53 = 47

Unknown angle for right triangle⬆️

Now we've calculated the two angles for the small triangle in the middle. So, we just have to calculate the top angle of the middle triangle:

180 - 68 - 47 = 65

The angle 65° and angle of x are vertical angle.(both are equal)

So... <u>x= 65°</u>

<em>hope it </em><em>helps </em><em>:</em><em>)</em>

4 0
3 years ago
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