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Fudgin [204]
3 years ago
13

. -5, 10, 7, 10, 9, 0, 1, 9, -1, 5 Work out the mean.

Mathematics
1 answer:
bezimeni [28]3 years ago
4 0

Answer:

6

Step-by-step explanation: because its online

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Can the numbers 24, 32, 40 be the lengths of the three sides of a right triangle? Explain why or why not.
nlexa [21]
Yes they can bc they are all odd
7 0
3 years ago
Without using a calculator, fill in the blanks with two
Akimi4 [234]

Answer:

Pretty sure its 7 and 8

Step-by-step explanation:

test it out

5 0
3 years ago
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steven has a rectangular rug with a perimeter of 16 feet the width of the rug is 5 feet what is the length of the rug
stich3 [128]
So perimeter is equal to 2 lengths and 2 width so the equation would be P=2L+2W. you know width so you plug in 5 for W then solve for L and you should get L=3
3 0
3 years ago
How many times can 2 go into 245 in fraction form​
zzz [600]

Answer:

244 1/1

Step-by-step explanation:

Since 2 goes into 245 122 times with 1 left over, it would be 244 and a whole, it would probably just be 244 and 1/1 or 245 but you asked for fraction so 244 1/1

5 0
3 years ago
Factor completely x^8- 16.
Nataly_w [17]

Answer:

Step-by-step explanation:


So in this example we'll be using the difference of squares which essentially states that: (a-b)(a+b)=a^2-b^2 or another way to think of it would be: a-b=(\sqrt{a}-\sqrt{b})(\sqrt{a}+\sqrt{b}). So in this example you'll notice both terms are perfect squares. in fact x^n is a perfect square as long as n is even. This is because if it's even it can be split into two groups evenly for example, in this case we have x^8. so the square root is x^4 because you can split this up into (x * x * x * x) * (x * x * x * x) = x^8. Two groups with equal value multiplying to get x^8, that's what the square root is. So using these we can rewrite the equation as:

x^8-16 = (x^4-4)(x^4+4)

Now in this case you'll notice the degree is still even (it's 4) and the 4 is also a perfect square, and it's a difference of squares in one of the factors, so it can further be rewritten:

x^4-4 = (x^2-2)(x^2+2)

So completely factored form is: (x^2-2)(x^2+4)(x^4+4)

I'm assuming that's considered completely factored but you can technically factor it further. While the identity difference of squares technically only applies to difference of squares, it can also be used on the sum of squares, but you need to use imaginary numbers. Because x^2+4 = x^2-(-4). and in this case a=x^2 and b=-4. So rewriting it as the difference of squares becomes: x^4+4 = x^4 - (-4) = (x^2-\sqrt{-4})(x^2+\sqrt{-4}) = (x^2-2i)(x^2+2i) just something that might be useful in some cases.

7 0
2 years ago
Read 2 more answers
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