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netineya [11]
3 years ago
5

What are the zeros of the function y=2x^2-3x-20

Mathematics
1 answer:
4vir4ik [10]3 years ago
4 0
-2.5 and 4

You can get this by factoring to the equation (2x + 5)(x - 4)
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Write the equation of the line that passes through (−2, 6) and (2, 14) in slope-intercept form.
MakcuM [25]
Slope-intercept form is y = mx + b, where m is the slope and b is the y-intercept.

The first step is to find the slope using the provided coordinates (-2, 6) and (2, 14). We can do that using the y1 - y2 / x1 - x2, like so:

6 - 14 / -2 - 2
-8 / -4
2

The slope is two, so we immediately know the answer is either A or B.

Now, plot the two points on graphing paper and determine where the line intersects the y-axis to find the y-intercept...

My graph shows the line intersecting the y-axis at 10, therefore the correct answer is:
y = 2x + 10
5 0
3 years ago
HElp ill give 10 points!!!!!!!!!!!!!
Evgesh-ka [11]

PLZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZAnswer:

Step-by-step explanation:

4 0
3 years ago
FlybynightSavings.com is offering a savings account that pays 28% compounded continuously. How much interest would a deposit of
Helga [31]
P =$3000, r = 28% , t = 5 years
<span>A = 3000.e^(0.28)(5) = 3000.(4.0551) = $12,165.60</span>
5 0
3 years ago
Answer please show steps please
erik [133]

Answer:

25 girls

Step-by-step explanation:

Let

x denote number of boys

and

y denote number of girls

According to the statement that total 45 people came,

x+y = 45      => Eqn 1

And total paid amount was 175

So,

5x + 3y = 175    => Eqn 2

For solving, We will use the substitution method

So, from eqn 1

x = 45-y

Putting value of x in eqn 2

5(45-y) +3y = 175

225 - 5y + 3y = 175

-2y+225 = 175

-2y = 175-225

-2y = -50

2y = 50

y = 25

Putting y =25 in eqn 1

x+25 = 45

x = 45 - 25

x = 20

As y= 25

So, 25 girls came to the dance ..

6 0
3 years ago
The computer that controls a bank's automatic teller machine crashes a mean of 0.6 times per day. What is the probability that,
professor190 [17]

Answer:

0.2103 = 21.03% probability that, in any seven-day week, the computer will crash less than 3 times.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given interval.

Mean of 0.6 times a day

7 day week, so \mu = 7*0.6 = 4.2

What is the probability that, in any seven-day week, the computer will crash less than 3 times? Round your answer to four decimal places.

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2)

In which

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-4.2}*(4.2)^{0}}{(0)!} = 0.0150

P(X = 1) = \frac{e^{-4.2}*(4.2)^{1}}{(1)!} = 0.0630

P(X = 2) = \frac{e^{-4.2}*(4.2)^{2}}{(2)!} = 0.1323

So

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0.0150 + 0.0630 + 0.1323 = 0.2103

0.2103 = 21.03% probability that, in any seven-day week, the computer will crash less than 3 times.

3 0
3 years ago
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