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Bas_tet [7]
3 years ago
15

Your class sells 64 tickets to a play.

Mathematics
1 answer:
HACTEHA [7]3 years ago
3 0
You sold 43 adult tickets
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I need help plz<br> i will mark you brainlest
Dovator [93]

Answer:

\frac{7}{4}  -  \frac{3}{4} =  \frac{4}{4}

Step-by-step explanation:

To find the number midway between 3/2 and 4/2, add them up and divide by 2

we have, 3/2 + 4/2 = 7/2

7/2 ÷ 2 = 7/4

Repeat the same for the number midway between 1/2 and 2/2 to get 3/4

The answer then is, 7/4 - 3/4 = 4/4

8 0
2 years ago
12=y-3y what's the answer
nevsk [136]
12=y-3y  Combine like terms
12=-2y  Divide
y=-6
8 0
3 years ago
Read 2 more answers
Can i please have more daily answers please.
V125BC [204]
No maaaaaaaaaaaaaaaaaam
4 0
3 years ago
Read 2 more answers
Solve: 92x + 1 = 93x – 2
vichka [17]

Answer:

x equals 3 :) if i helped, please give brainliest!

Step-by-step explanation:

6 0
3 years ago
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The game of Connex contains one 4-unit piece, two identical 3-unit pieces, three identical 2-unit pieces and four identical 1-un
Aleks [24]

Answer: 277 ways

Step-by-step explanation:

Let’s start bycreating 10-unit pieces using the 4-unit piece.

The arrangements are:

1). 4-3-3 (3 permutations)

2). 4-3-2-1 = 4! = 24 permutations.

3). 4-3-1-1-1 (5*[4!/(3!1!)]

= 5*4

= 20permutations

4). 4-2-2-2 (4 permutations)

5). 4-2-2-1-1 (5 *[4!/(2!2!)]

= 5*6

= 30 permutations

6). 4-2-1-1-1-1(6*[5!/(4!1!)]

= 6*5

= 30 permutations

Let’s-consider the arrangements using one or more3-unit pieces and no 4-unit piece:

7). 3-3-2-2 (4!/(2!2!)

8). 3-3-2-1-1 (5*(4!/(2!2!)

= 5*6

= 30 permutations.

9). 3-3-1-1-1-1 (6!/(4!2!) = 0

10). 3-2-2-2-1 (5*4!/(3!1!)

= 5*4

= 20permutations

11). 3-2-2-1-1-1 (6*5!/(3!2!)

= 6*10

= 60 permutations

Finally we would look at the arrangements using only 1-and 2-unit pieces:

12). 2-2-2-1-1-1-1 (7!/(4!3!)

= 35 permutations

add them all up:

(3 + 24 + 20 + 4) + (30 + 30 + 6 + 30) + (15 + 20 + 60 + 35)

=51 + 96 + 130

= 277ways

5 0
2 years ago
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